Answer:
The speed of a wave would be 18 with a wavelength of 2 m and a frequency of 9 Hz.
Complete question is;
a. Two equal sized and shaped spheres are dropped from a tall building. Sphere 1 is hollow and has a mass of 1.0 kg. Sphere 2 is filled with lead and has a mass of 9.0 kg. If the terminal speed of Sphere 1 is 6.0 m/s, the terminal speed of Sphere 2 will be?
b. The cross sectional area of Sphere 2 is increased to 3 times the cross sectional area of Sphere 1. The masses remain 1.0 kg and 9.0 kg, The terminal speed (in m/s) of Sphere 2 will now be
Answer:
A) V_t = 18 m/s
B) V_t = 10.39 m/s
Explanation:
Formula for terminal speed is given by;
V_t = √(2mg/(DρA))
Where;
m is mass
g is acceleration due to gravity
D is drag coefficient
ρ is density
A is Area of object
A) Now, for sphere 1,we have;
m = 1 kg
V_t = 6 m/s
g = 9.81 m/s²
Now, making D the subject, we have;
D = 2mg/((V_t)²ρA))
D = (2 × 1 × 9.81)/(6² × ρA)
D = 0.545/(ρA)
For sphere 2, we have mass = 9 kg
Thus;
V_t = √[2 × 9 × 9.81/(0.545/(ρA) × ρA))]
V_t = 18 m/s
B) We are told that The cross sectional area of Sphere 2 is increased to 3 times the cross sectional area of Sphere 1.
Thus;
Area of sphere 2 = 3A
Thus;
V_t = √[2 × 9 × 9.81/(0.545/(ρA) × ρ × 3A))]
V_t = 10.39 m/s
The period of the pendulum is 6 seconds.
<h3>What is period?</h3>
Period is the time taken for a simple pendulum to move to(forward) and fro(backward). The s.i unit of period is seconds(s).
Note: When a simple pendulum moves to and fro. it completes one cycle.
From the question, The period of the pendulum is calculated using the formula below.
<h3>Formula</h3>
- T = a+b.............. Equation 1
Where:
- T = Period of the pendulum
- a = Time taken for the pendulum to move forward
- b = Time taken for the pendulum to move backward.
From the question,
Given:
Substitute the values above into equation 1
Hence, The period of the pendulum is 6 seconds.
Learn more about period here: brainly.com/question/21924087
Answer:
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Explanation:
I'm in forensic science :)
