Answer:
Inductive resistance of the coil 120 kΩ
Explanation:
Given:
L = 20 mH = 0.020 H - Coil inductance
f = 950 kHz = 950 000 Hz - Frequency
______________
XL - ? Inductive resistance of the coil
XL = 2·π·f·L
XL = 2·3.14·950000·0.020 ≈ 120 000 Ω or XL = 120 kΩ
∆g for these initial partial pressures is 10,403.31 KJ.
ΔG gets increasingly positive as a product gas's partial pressure is raised. ΔG becomes more negative as the partial pressure of a reactant gas increases.
∆g = RT ln (q/k)
In this equation: R = 8.314 J mol⁻¹ K⁻¹ or 0.008314 kJ mol⁻¹ K⁻¹
K = 325
If ΔG < 0, then K > Q, and the reaction must proceed to the right to reach equilibrium.
∴∆g = RT ln (q/k)
= 8.314 × 298 ln ( 5 / 325)
= 2477.57 ln 0.015
= 2477.57 × (-4.199)
= 10,403.31 KJ
Products are preferred over reactants at equilibrium if G° 0 and both the products and reactants are in their standard states. When reactants are preferred above products in equilibrium, however, if G° > 0, K 1. At equilibrium, neither reactants nor products are preferred if G° = 0, hence K = 1.
Therefore, ∆g for these initial partial pressures is 10,403.31 KJ.
Learn more about equilibrium here:
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Define and measure the speed
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