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juin [17]
3 years ago
8

A 2.0-ohm resistor is connected in a series with a 20.0 -V battery and a three-branch parallel network with branches whose resis

tance are 8.0 ohms each. Ignoring the battery’s internal resistance, what is the current in the batter? Show your work.
Physics
1 answer:
Llana [10]3 years ago
4 0

Answer:

Explanation:

Resolving the parallel resistor branches

\frac{1}{Rtotal} =\frac{1}{8.0ohm} +\frac{1}{8.0ohm} +\frac{1}{8.0ohm} =2.67Ohm

The equivalent resistor is now in series with the 2.0 Ohm resistor

so, by using Ohm's Law

I=\frac{V}{Rtotal+R} \\I=\frac{20.0V}{2.67Ohm+2.0Ohm} \\\\I= 4.28A

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If the near-point distance of the jeweler is 22.0 cm, and the focal length of the magnifying glass is 7.70 cm, find the angular
Strike441 [17]

Answer: The angular magnification M = 2.1

Explanation:

If the jeweler holds the diamond at the focal point of the magnifying glass, its image will be produced infinitely far away.

This gives an angular magnification of M = N/f

Since the diamond is held 5.68 cm from the magnifying glass,

Then, M = (N - 5.68)/f

Where N = 22.0 cm and f = 7.7 cm

M = (22 - 5.68)/7.7

M = 2.1

5 0
3 years ago
A 45 kg man is running 22 m/s. Calculate the kinetic energy
Eddi Din [679]

Answer:

<h2>10890 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 45 \times  {22}^{2}  \\  =  \frac{1}{2}  \times 45 \times 484 \\  = 45 \times 242 \\  = 10890

We have the final answer as

<h3>10890 J</h3>

Hope this helps you

6 0
3 years ago
Can anyone help me with this question?
AVprozaik [17]

Answer:

Answers should be:

A, and B

Explanation:

Hope this helps.

6 0
3 years ago
Solved, just need someone to check! thank you. ​
Lady bird [3.3K]

Answer:

good job keep it up

Explanation:

3 0
3 years ago
A satellite is in a circular orbit around the Earth at an altitude of 3.18x10 m. Find the period and th orbital speed of the sat
Leona [35]

Answer:

112.17 m/s

56.427 years

Explanation:

h = 3.18 x 10^10 m

R = 6.4 x 10^6 m

r = R + h = 3.18064 x 10^10 m

M = 6 x 10^24 kg

The formula for the orbital velocity is given by

v = \sqrt{\frac{G M }{r}}

v = \sqrt{\frac{6.67 \times 10^{-11}\times 6\times 10^{24}  }{3.18064\times 10^{10}}}

v = 112.17 m/s

Orbital period, T = 2 x 3.14 x 3.18064 x 10^10 / 112.17

T = 0.178 x 10^10 s

T = 56.427 years

8 0
3 years ago
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