Answer:
8.37×10⁻³ C.
Explanation:
The formula of electric field is given as
E = kq/r².......................... Equation 1
Where E = electric field, q = amount of charge, k = coulomb constant, r = radius of the sphere
make q the subject of the equation
q = Er²/k .................... Equation 2
Given: E = 3.01×10⁶ N/C, r = 5.0 m, k = 8.99×10⁹ Nm²/C².
Substitute into equation 2
q = (3.01×10⁶)(5²)/(8.99×10⁹)
q = (75.25/8.99)×10⁻³
q = 8.37×10⁻³ C.
Hence the maximum amount of charge = 8.37×10⁻³ C.
