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madreJ [45]
3 years ago
14

The suspension cable of a 1,000 kg elevator snaps, sending the elevator moving downward through its shaft. The emergency brakes

of the elevator stop the elevator shortly before it reaches the bottom of the shaft. If the elevator fell a distance of 100 m starting from rest, the heat that the brakes must dissipate to bring the elevator safely to rest is (A) 100 J (B) 1,000 J (C) 10,000 J (D) 100,000 J (E) 1,000,000 J
Physics
1 answer:
tester [92]3 years ago
4 0

Answer:

option (E) 1,000,000 J

Explanation:

Given:

Mass of the suspension cable, m = 1,000 kg

Distance, h = 100 m

Now,

from the work energy theorem

Work done by the gravity = Work done by brake

or

mgh = Work done by brake

where, g is the acceleration due to the gravity = 10 m/s²

or

Work done by brake  = 1000 × 10 × 100

or

Work done by brake = 1,000,000 J

this work done is the release of heat in the brakes

Hence, the correct answer is option (E) 1,000,000 J

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Two charged concentric spherical shells have radii of 11.0 cm and 14.0 cm. The charge on the inner shell is 3.50 ✕ 10−8 C and th
Sergio039 [100]

Answer:

The magnitude of the electric field are 2.38\times10^{4}\ N/C and 1.09\times10^{4}\ N/C

Explanation:

Given that,

Radius of inner shell = 11.0 cm

Radius of outer shell = 14.0 cm

Charge on inner shell q_{inn}=3.50\times10^{-8}\ C

Charge on outer shell q_{out}=1.60\times10^{-8}\ C

Suppose, at r = 11.5 cm and at r = 20.5 cm

We need to calculate the magnitude of the electric field at r = 11.5 cm

Using formula of electric field

E=\dfrac{kq}{r^2}

Where, q = charge

k = constant

r = distance

Put the value into the formula

E=\dfrac{9\times10^{9}\times3.50\times10^{-8}}{(11.5\times10^{-2})^2}

E=2.38\times10^{4}\ N/C

The total charge enclosed  by a radial distance 20.5 cm

The total charge is

q=q_{inn}+q_{out}

Put the value into the formula

q=3.50\times10^{-8}+1.60\times10^{-8}

q=5.1\times10^{-8}\ C

We need to calculate the magnitude of the electric field at r = 20.5 cm

Using formula of electric field

E=\dfrac{kq}{r^2}

Put the value into the formula

E=\dfrac{9\times10^{9}\times5.1\times10^{-8}}{(20.5\times10^{-2})^2}

E=1.09\times10^{4}\ N/C

Hence, The magnitude of the electric field are 2.38\times10^{4}\ N/C and 1.09\times10^{4}\ N/C

7 0
3 years ago
One end of a thin rod is attached to a pivot, about which it can rotate without friction. Air resistance is absent. The rod has
Scrat [10]

Answer:

5.24 m/s

Explanation:

So for the rod to be able to rise upward to the straight up position, the kinetic energy caused by linear speed v0 must be just enough to convert into the potential energy.

Since the rod is uniform in mass, we can treat the body as 1 point, at its center of mass, or geometric center, aka 0.35 / 2 = 0.175 m from the pivot.

For the rod to swing from bottom to top, the center must have moved a distance of h = 0.175 * 2 = 0.35 m, vertically speaking.

Since we neglect friction and air resistance, according to the law of energy conservation then:

E_k = E_p

mv^2/2 = mgh

Where v is the speed at the center of mass, g = 9.81 m/s2 is the gravitational acceleration, and m is the mass. We can divide both sides by m

v^2 = 2gh = 2*9.81*0.35 = 6.867

v = \sqrt{6.867} = 2.62 m/s

As this is only the speed at the center of mass, the speed at the bottom end would be different, to calculate this, we need to find the common angular speed:

\omega = v / r = 2.62 / 0.175 = 14.97 rad/s

Where r is the rotation radius, or the distance from pivot point to the center of mass

v_0 = \omega R = 14.97*0.35 = 5.24 m/s

Where R is the distance from the pivot to the bottom end of the rod

5 0
3 years ago
Once an object enters orbit, what keeps the object moving sideways?
yaroslaw [1]

It's the natural tendency of things to keep going unless there's something trying to stop them.

It's usually called "inertia".

Don't get the idea from all of this that things stop unless there's something to keep them going.  The truth is exactly the opposite:  Things keep going unless there's something to make them stop.

7 0
3 years ago
Read 2 more answers
a kickball is struck with a 15.2 m/s velocity at a 63.0 degree angle. it lands on a rooftop 2.40 s later. how high is the roof?​
Serhud [2]

Refer to the attachment

3 0
3 years ago
Some one help my science homework is due tomorrow and I'm so stuck with question 8-9, and 11-12
yuradex [85]
Off the top of my head, I only know 9 and 11, so I'll answer those two.

9) A heterotroph is an organism that relies on other organisms for food/energy
    An autotroph can produce its own food from inorganic compounds (light)

11) Vascular plants have specialized tubes for transporting nutrients
      Nonvascular plants do not have such tubes and are simpler
5 0
3 years ago
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