Answer:
Explanation:
1 ) The superball which bounces back with the same velocity will be more effective at closing the door . It creates greater impulse on the door because it creates more change in momentum .
2 ) The final momentum of the clay ball will be zero because its velocity after collision will be zero.
3 ) The area of force - time graph gives the value of impulse.
4 ) When the collision is made on a perfect spring , it becomes perfectly elastic . In this case the velocity of recoil is same as that before the collision . So there is no loss of energy in the collision.
5 ) The change in momentum will give the value of impulse. Since we can calculate the velocity before and after the collision , we can calculate the value of impulse. If m be the mass and v be the value of velocity before the collision
impulse = change in momentum
= m v - ( - mv )
= 2m v.
The average speed of the car is 19.62 km/hr.
'<em>Your question is not complete, it seems to be missing the following information'</em>
find the average speed of the car
The given parameters;
initial velocity of the car, u = 25 km/hr
time of motion of the car, t= 1.5 hr
final velocity, v = 21 km/h
time of motion, = 1.25 hr
The average speed of the car is calculated as follows;
![average \ velocity = \frac{total \ distance }{total \ time} \\\\average \ velocity = \frac{(25 km/h \times 1.5h)+(21km/h\times 1.25hr)}{(1.5h + 0.5h + 1.25h)} \\\\average \ velocity = 19.62 \ k m/hr](https://tex.z-dn.net/?f=average%20%5C%20velocity%20%3D%20%5Cfrac%7Btotal%20%5C%20distance%20%7D%7Btotal%20%5C%20time%7D%20%5C%5C%5C%5Caverage%20%5C%20velocity%20%3D%20%20%5Cfrac%7B%2825%20km%2Fh%20%5Ctimes%201.5h%29%2B%2821km%2Fh%5Ctimes%201.25hr%29%7D%7B%281.5h%20%2B%200.5h%20%2B%201.25h%29%7D%20%5C%5C%5C%5Caverage%20%5C%20velocity%20%3D%2019.62%20%5C%20k%20m%2Fhr)
Thus, the average speed of the car is 19.62 km/hr.
Learn more here: brainly.com/question/17289046
Answer:
Explanation:
Assuming the x axis lies along the slope.
Fy = mgcosθ = 1150(9.81)cos8.70 = 11,151.6937... = 11.2 kN
Answer:
Riegel's velocity relative to us is: ![v_{r} = 2.07 * 10^4 m/s](https://tex.z-dn.net/?f=v_%7Br%7D%20%3D%202.07%20%2A%2010%5E4%20m%2Fs)
Explanation:
Frequency of Riegel's spectrum, ![f_{r} = f - f'](https://tex.z-dn.net/?f=f_%7Br%7D%20%3D%20f%20-%20f%27)
![f' = f - f_{r} = 4.26 * 10^{10} Hz](https://tex.z-dn.net/?f=f%27%20%3D%20f%20-%20f_%7Br%7D%20%3D%204.26%20%2A%2010%5E%7B10%7D%20Hz)
From the relativistic doppler effect, the wavelength of Riegel's spectrum is:
![\lambda = \lambda_{r} (1 - \frac{v_{r} }{c} )\\\frac{c}{f} = \frac{c}{f_r} (1 - \frac{v_{r} }{c} )\\v_{r} = (\frac{f - f_r}{f} )c\\Since, f' = f - f_r\\v_{r} = (\frac{f'}{f} )c\\v_{r} = (\frac{4.26 * 10^{10}}{6.17 * 10^{14}} ) * (3 * 10^8)\\v_{r} = 2.07 * 10^4 m/s](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Clambda_%7Br%7D%20%281%20-%20%5Cfrac%7Bv_%7Br%7D%20%7D%7Bc%7D%20%29%5C%5C%5Cfrac%7Bc%7D%7Bf%7D%20%3D%20%5Cfrac%7Bc%7D%7Bf_r%7D%20%281%20-%20%5Cfrac%7Bv_%7Br%7D%20%7D%7Bc%7D%20%29%5C%5Cv_%7Br%7D%20%3D%20%28%5Cfrac%7Bf%20-%20f_r%7D%7Bf%7D%20%29c%5C%5CSince%2C%20f%27%20%3D%20f%20-%20f_r%5C%5Cv_%7Br%7D%20%3D%20%28%5Cfrac%7Bf%27%7D%7Bf%7D%20%29c%5C%5Cv_%7Br%7D%20%3D%20%28%5Cfrac%7B4.26%20%2A%2010%5E%7B10%7D%7D%7B6.17%20%2A%2010%5E%7B14%7D%7D%20%29%20%2A%20%283%20%2A%2010%5E8%29%5C%5Cv_%7Br%7D%20%3D%202.07%20%2A%2010%5E4%20m%2Fs)