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alexandr1967 [171]
3 years ago
14

What happens when one force acts on an object?​

Physics
1 answer:
Pachacha [2.7K]3 years ago
5 0

Answer:

if the weight of the object is equal to the force applied, there will be no change

if the force applied is less than the weight of the object, there won't be any change

if the force application ed is greater than the weight of the object, than the object will move.

Explanation:

here the weight referred to the force of the object.

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A beam of light from a laser illuminates a glass how long will a short pulse of light beam take to travel the length of the glas
Eduardwww [97]

Answer:

The time of short pulse of light beam is 2.37\times10^{-9}\ sec

Explanation:

Given that,

A beam of light from a laser illuminates a glass.

Suppose, the length of piece is L=25.21\times10^{-2}\ m

Index of refraction is 2.83.

We need to calculate the speed of light pulse in glass

Using formula of speed

v=\dfrac{c}{\mu}

Put the value into the formula

v=\dfrac{3\times10^{8}}{2.83}

v=1.06\times10^{8}\ m/s

We need to calculate the time of short pulse of light beam

Using formula of velocity

v=\dfrac{d}{t}

t=\dfrac{d}{v}

Put the value into the formula

t=\dfrac{25.21\times10^{-2}}{1.06\times10^{8}}

t=2.37\times10^{-9}\ sec

Hence, The time of short pulse of light beam is 2.37\times10^{-9}\ sec

3 0
4 years ago
Calculate the centripetal force (in N) on the end of a 44 m (radius) wind turbine blade that is rotating at 0.7 rev/s. Assume th
Andrews [41]
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4 0
3 years ago
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A pebble is dropped from rest from the top of a tall cliff and falls 53.4 m after 3.3 s has elapsed. How much farther does it dr
jeka94

Answer:

426.84 m

Explanation:

initial velocity u = 0

time t = 3.3 s

distance travelled s = 53.4 m

acceleration due to gravity = g

s = ut + 1/2 g t²

53.4 = 0 + 1/2 g x 3.3²

g = 9.8 m /s²

For the whole length of fall

distance travelled = h

total time = 6.6 + 3.3 = 9.9 s

h = ut + 1/2 g t²

u again = 0

h = .5 x 9.8 x 9.9²

= 480.24 m

distance travelled in last 6.6 s

= 480.24 - 53.4

= 426.84 m

6 0
3 years ago
How would you differentiate the theoretical and actual velocities of PE and KE in falling objects?
Solnce55 [7]

Answer: you've been trolled

Explanation:

8 0
3 years ago
The Achilles tendon connects the muscles in your calf to the back of your foot. When you are sprinting, your Achilles tendon alt
zepelin [54]

Answer:

a)5mm

b)3.3%

Explanation:

first note down the what's given

Y_{tendon} = 0.15x10^{10} N/m^{2}

Area=A= 1.1x10^{-4} m^{2}

Mass of the runner=m_{r}=70kg

Fmax= 8 F (since tendon can stretch 8 times of runner's weight)

= 8 m_{r}g=8 x 70 x 9.8=> 5488N

L=15cm=> 0.15m

a)We know that, Y={Fmax.L}/AΔL

YAΔL=Fmax. L

ΔL=\frac{Fmax L}{YA} =\frac{5488*0.15}{0.15x10^{10}x1.1x10^{-4}  }

ΔL=4.99x10^{-3} m => 5mm

b) L=15cm= 150mm

Fractional change can be determined by,

(ΔL/L) *100

=\frac{4.99}{150} *100

=3.33%

8 0
3 years ago
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