Heya!!
For calculate aceleration, lets applicate second law of Newton:
<u>Δ Being Δ</u>
F = Force = 183 N
m = Mass = 367 kg
a = Aceleration = ?
⇒ Let's replace according the formula and clear "a":
⇒ Resolving
Result:
The aceleration is <u>0,49 meters per second squared (m/s²)</u>
Good Luck!!
<h2>
Answer:</h2>
<em><u>Velocity of throwing arrow = 43.13 m/s.</u></em>
<h2>
Explanation:</h2>
In the question,
Let us say the height from which the arrow was shot = h
Distance traveled by the arrow in horizontal = 61 m
Angle made by the arrow with the ground = 2°
So,
From the <u>equations of the motion</u>,
Now,
Also,
Finally, the angle made is 2 degrees with the horizontal.
So,
Final horizontal velocity = v.cos20°
Final vertical velocity = v.sin20°
Now,
u = v.cos20° (No acceleration in horizontal)
Also,
So,
We can say that,
<em><u>Therefore, the velocity with which the arrow was shot by the archer is 43.13 m/s.</u></em>
Answer:
Explanation:
In the calculation of distance we do not take into account the direction of movement .So only magnitude of movement is taken care of.
On the other hand , in respect of displacement , we take into account even direction of movement along with magnitude.
Distance covered by flea = 45 - 27 = 18 cm
Displacement by flea = 27 - 45 = - 18 cm
Speed = Distance covered / time
= 18 / 3 = 6 cm / s
Velocity = - 18 / 3 = - 6 cm /s.