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svlad2 [7]
3 years ago
11

PROJECTILE MOTION FOR TWO Rocks-VELOCITY-TIME GRAPHS

Physics
1 answer:
erastova [34]3 years ago
5 0

Answer:

nob

nobody knows i tried it doesnt work like that ask for help

Explanation:

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1. During a medieval siege of a castle, the attacking army uses a trebuchet to hurl heavy stones at the castle walls. If the tre
Grace [21]
Initial velocity u = 40 
Angle at launch = 55 degrees
 At maximum height v = 0, velocity equation v^2 = u^2 - 2gh,
 0 = (40 x sin55)^2 - 2 x 9.81 x h => (40 x 0.819)^2 = 19.62h => h = 32.76^2 /
19.62
 Maximum height = 54.7 m 
 We have v = u - gt => 0 = (40 x sin55) - 9.81 x t => t = 32.76 / 9.81 => t =
3.34 s
 Time taken to hit the ground is 2t = 2 x 3.34 = 6.68 s 
Distance from castle to trebuchet = utcos55 = 40 x 6.68 x 0.573 = 153.1 m
8 0
4 years ago
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