Answer:
6.23 KOH 90% son necesarios
Explanation:
Una solución 1N de KOH requiere 1equivalente (En KOH, 1eq = 1mol) por cada litro de solución.
Para responder esta pregunta se requiere hallar los equivalentes = Moles de KOH para preparar 100mL = 0.100L de una solución 1N. Haciendo uso de la masa molar de KOH y del porcentaje de pureza del KOH se pueden calcular los gramos requeridos para preparar la solución así:
<em>Equivalentes KOH:</em>
0.100L * (1eq / L) = 0.100eq = 0.100moles
<em>Gramos KOH -Masa molar: 56.1056g/mol-:</em>
0.100moles * (56.1056g/mol) = 5.61 KOH se requieren
<em>KOH 90%:</em>
5.61g KOH * (100g KOH 90% / 90g KOH) =
<h3>6.23 KOH 90% son necesarios</h3>
Answer:Um... I think 5000 i am not really sure
Explanation: I Dont Really Know
Gravitational force will increase with greater mass
696.32 mmHg is the final pressure of the gas.
<h3>What is an ideal gas equation?</h3>
The ideal gas equation, pV = nRT, is an equation used to calculate either the pressure, volume, temperature or number of moles of a gas.
Given data:
= 720 mmHg
= ?
= 2.5 mol
= 3.2 mol
= 34 L
= 45 L
Formula
Combined gas law
= 696.32 mmHg
Hence, 696.32 mmHg is the final pressure of the gas.
Learn more about an ideal gas equation here:
brainly.com/question/19251972
#SPJ1
