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2 years ago

A cube of some rock weighs 6 grams, and a same-sized cube of water weighs 2 grams. What is the specific gravity of this rock?

Chemistry

1 answer:

PSYCHO15rus [73]2 years ago

5 0

Answer:

The specific gravity of the rock with respect to water is equal to 3

Explanation:

To solve the question, we list out the variables as follows

Mass of rock = 6 grams

Mass of equal volume of water = 2 grams

Specific gravity or relative density is the mass of a unit volume of a substance divided by the mass of an equal volume of a reference material.

Specific gravity = (mass of substance)/(mass of equal volume of water)

Therefore the specific of the rock sample is = (mass of cube of rock sample)/(mass of same-sized cube of water)

= (6 grams)/(2 grams) = 3

The specific gravity of the rock = 3

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3 years ago

A fixed mass of oxygen gas occupies 300cm cube at 0 degree centigrade. what volume would the gas occupy at 15 degree centigrade

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Volume occupied by oxygen gas at 15 degree centigrade is equal to $316.5$ centimeter cube

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where T1 and T2 are temperature in Kelvin

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2 years ago

As an EPA scientist studying catalytic converters and urban smog, you want to find Kc for the following reaction: 2NO2(g) ⇋ N2(g

Bas_tet [7]

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Explanation:

the desired reaction is

2 NO₂(g) ⇋ N₂(g) + 2 O₂(g)

Kc =[N₂]*[O₂]² /[NO₂]²

Since

1/2 N₂(g) + 1/2 O₂(g) ⇋ NO(g)

Kc₁= [NO]/(√[N₂]√[O₂]) → Kc₁²= [NO]²/([N₂][O₂])

and

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then

Kc₁²* (1/Kc₂) = [NO]²/([N₂]*[O₂]) *[NO₂]²/([NO]²[O₂]) = [NO₂]²/([N₂]*[O₂]²) = 1/Kc

Kc₁² /Kc₂ = 1/Kc

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