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3 years ago

PLEASE HELPPPPP I WULL MARK BRAINLEIST

Chemistry

1 answer:

ANEK [815]3 years ago

8 0

Answer:

the answer is: 10

Explanation:

To find density you do mass divided by volume

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The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentrati

a_sh-v [17]

Answer : The concentration of NOBr after 95 s is, 0.013 M

Explanation :

The integrated rate law equation for second order reaction follows:

$k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)$

where,

k = rate constant = $0.80M^{-1}s^{-1}$

t = time taken = 95 s

[A] = concentration of substance after time 't' = ?

$[A]_o$ = Initial concentration = 0.86 M

Now put all the given values in above equation, we get:

$0.80=\frac{1}{95}\left (\frac{1}{[A]}-\frac{1}{(0.86)}\right)$

[A] = 0.013 M

Hence, the concentration of NOBr after 95 s is, 0.013 M

4 0

3 years ago

For a process Arightwards harpoon over leftwards harpoonB, at 25 °C there is 10% of A at equilibrium while at 75 °C, there is 80

Lostsunrise [7]

This question is describing the following chemical reaction at equilibrium:

$A\rightleftharpoons B$

And provides the relative amounts of both A and B at 25 °C and 75 °C, this means the equilibrium expressions and equilibrium constants can be written as:

$K_1=\frac{90\%}{10\%}=9\\\\K_2=\frac{20\%}{80\%} =0.25$

Thus, by recalling the Van't Hoff's equation, we can write:

$ln(K_2/K_1)=-\frac{\Delta H}{R}(\frac{1}{T_2} -\frac{1}{T_1} )$

Hence, we solve for the enthalpy change as follows:

$\Delta H=\frac{-R*ln(K_2/K_1)}{(\frac{1}{T_2} -\frac{1}{T_1} ) }$

Finally, we plug in the numbers to obtain:

$\Delta H=\frac{-8.314\frac{J}{mol*K} *ln(0.25/9)}{[\frac{1}{(75+273.15)K} -\frac{1}{(25+273.15)K} ] } \\\\\\\Delta H=4,785.1\frac{J}{mol}$

Learn more:

5 0

3 years ago

HELP ME PLEASEEE- 8th grade science

icang [17]

Answer:

It's obviously LIGHT ENERGY for me cuz it's from the flashlight..

Explanation:

Hope it helps you..

Your welcome in advance..

(ㆁωㆁ)

3 0

3 years ago

A gas in a sealed container had its volume increased from 12.1 liters to 21.1 liters.

ArbitrLikvidat [17]

Answer:

The answer to your question is P2 = 170.9 torr

Explanation:

Data

Volume 1 = 12.1 l Volume 2 = 21.1 l

Temperature 1 = 241 °K Temperature 2 = 298°K

Pressure 1 = 546 torr Pressure 2 = ?

Process

To solve this problem use the combined gas law.

P1V1/T1 = P2V2/T2

-Solve for P2

P2 = T1V1T2 / T1V2

-Substitution

P2 = (241 x 12.1 x 298) / (241 x 21.1)

-Simplification

P2 = 868997.8 / 5085.1

-Result

P2 = 170.9 torr

8 0

4 years ago

PLEASE HELPPPP!!!!!

Likurg_2 [28]

Answer : The mass of nitric acid is, 214.234 grams.

Solution : Given,

Moles of nitric acid = 3.4 moles

Molar mass of nitric acid = 63.01 g/mole

Formula used :

$\text{Mass of }HNO_3=\text{Moles of }HNO_3\times \text{Molar mass of }HNO_3$

Now put all the given values in this formula, we get the mass of nitric acid.

$\text{Mass of }HNO_3=(3.4moles)\times (63..01g/mole)=214.234g$

Therefore, the mass of nitric acid is, 214.234 grams.

6 0

3 years ago