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3 years ago

Glucose is broken down in different ways, both in the presence and in the absence of oxygen.

2 answers:

8 0

MAY BE THE ANSWER IS (2) BECAUSE GLYCOSIS IS THE PROCESS IN WHICH THE CONVERSION OF 6 C GLUCOSE INTO PYRUVATE INSIDE THE CYTOPLASM

AveGali [126]3 years ago

4 0

Answer:

The Option 2

A. pyruvic acid, ATP, NADH

B. ATP, FADH2, NADH

C. ATP

D. NAD+

Explanation:

In glycolysis, which is the breakdown of glucose into two molecules of pyruvate with the release of energy, the major products are pyruvate, ATP and NADH, which is an energy electron carrier, and this process begins in the cytoplasm.

Krebs' Cycle occurs in the presence of oxygen releasing one molecule of guanosine triphosphate which donates one phosphate group to ADP to form ATP, three molecules of NAD which is then reduced to NADH, one molecule of FAD which is reduced to FADH2.

In electron transport chain, ATP is produced. In lactic acid fermentation, which is the pathway involved in the absence of oxygen releasing NAD+ as its major product.

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Combustion reactions are ones that always include elemental oxygen as a reactant. When a hydrocarbon (substance made up of carbo

inysia [295]

1. CH4 + 2O2 = CO2 + 2H20 B.

2. 2CH2H6 + 7O2 = 4CO2 + 6H20 A

3. C3H8 + 502 = 3CO2 + 4H20 C

<h3>
How to determine the appropriate products of reaction</h3>

To find the appropriate end products, use the following rules

The hydrogen ratio should be the same on both the product and reactant sides
The oxygen ratio should be the same on both the product and reactant sides
The carbon ratio should be the same on both sides.

Thus for equation;

1. CH4 + 2O2 = CO2 + 2H20 B.

2. 2CH2H6 + 2O2 = 4CO2 + 6H20 A

3. C2H8 + 502 = 2CO2 + 4H20 C

Learn more about balancing equations here:

brainly.com/question/26694427

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2 years ago

A compound is composed of only C, H, and O. The combustion of a 0.519-g sample of the compound yields 1.24 g of CO 2 and 0.255 g

vredina [299]

Answer:

$\large\boxed{\large\boxed{C_3H_3O}}$

Explanation:

1. Calculate the mass of C in 1.24 g of CO₂

$1.24gCO_2\times \dfrac{12.011gC}{44.01gCO_2}=0.3384gC$

2. Calculate the mass of H in 0.255g of H₂O

$0.255gH_2O\times \dfrac{2.016gH}{18.015gH_2O}=0.02854gH$

3. Calculate the mass of O by difference

$0.519g-0.3384g-0.02854g=0.15206g$

4. Convert every mass to number of moles:

C: 0.3384g / (12.011g/mol) = 0.02817 mol

H: 0.02854g / (1.008g/mol) = 0.02831 mol

O: 0.15206g / (15.999g/mol) = 0.009504 mol

5. Divide every number of moles by the least number of moles (0.009504):

C: 0.02817/0.009504 = 2.96 ≈ 3

H: 0.02831 / 0.009504 ≈ 3

O: 0.009504 / 0.009504 = 1

6. Those numbers are the respective subscripts in the empirical formula:

$C_3H_3O$

7 0

4 years ago

What were the success and failures that came to Boyle’s excitements?

Alenkinab [10]

To always try and never give up

4 0

4 years ago

Permanganate ion reacts in basic solution with oxalate ion to form carbonate ion and solid manganese dioxide. Balance the skelet

saw5 [17]

Answer:

2MnO4^- (aq) + 3C2O4^2- (aq) + 2H2O (l) --> 2MnO2(s) +6CO3^2 -(aq) + 4H^+ (aq)

Explanation:

First, write the half equations for the reduction of MnO4^- and the oxidation of C2O4^2- respectively. Balance it.

Reduction requires H+ ions and e- and gives out water, vice versa for oxidation.

Reduction:

MnO4^- (aq) + 4H^+ (aq) + 3e- ---> MnO2(s) + 2H2O (l)

Oxidation:

C2O4^2- (aq) + 2H2O (l) ---> 2CO3^2 -(aq) + 4H^+ (aq) + 2e-

Balance the no. of electrons on both equations so that electrons can be eliminated. we can do so by multiplying the reduction eq by 2, and oxidation eq by 3.

2MnO4^- (aq) + 8H^+ (aq) + 6e- ---> 2MnO2(s) + 4H2O (l)

3C2O4^2- (aq) + 6H2O (l) ---> 6CO3^2 -(aq) + 12H^+ (aq) + 6e-

Now combine both equations and eliminate repeating H+ and H2O.

2MnO4^- (aq) + 8H^+ (aq) + 3C2O4^2- (aq) + 6H2O (l) --> 2MnO2(s) + 4H2O (l) +6CO3^2 -(aq) + 12H^+ (aq)

turns into:

2MnO4^- (aq) + 3C2O4^2- (aq) + 2H2O (l) --> 2MnO2(s) +6CO3^2 -(aq) + 4H^+ (aq)

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4 years ago

The burning of gasoline in an automobile engine is an example of a(n) _____.

inysia [295]

It is an exothermic reaction because the heat is released.

6 0

3 years ago

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