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3 years ago

Acceleration usually has the symbol a. It is a vector. What is the correct way

Chemistry

2 answers:

olya-2409 [2.1K]3 years ago

7 0

Answer: D

The correct way of writing a vector is to put a bar (-) on it.

BaLLatris [955]3 years ago

3 0

Answer:

Explanation:

it has an arrow symbolizing direction because a vector quantity has both magnitude and direction.

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Plz answer this fast... will mark ur answer as brainliest

Xelga [282]

Answer:

When fuels are incompletely burnt, they release carbon monoxide gas into the atmosphere. This gas is very dangerous as it is poisonous in nature

Explanation:

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2 years ago

Read 2 more answers

A cube has a height of 8 cm and a mass of 457 g. What is its density?

ZanzabumX [31]

Answer:

the answer is b, 0.89

Explanation:

A cube has a height of 8 cm and a mass of 457 g. What is its density?

a. 233,984 g/cm

b. 0.89g/cm3

c. 1.12 g/cm3

Density = mass/volume

the volume of the cube is 8X8X8=512cm3

the mass is 457 gm

the density is 457/512 = 0.889 gm/cm3

the answer is b, 0.89

3 0

1 year ago

Alcano con 1 carbono?

never [62]

creo esto te va a ayudar

5 0

2 years ago

Will GIVE BRAINLIEST --A student makes a standard solution of potassium hydroxide by adding 14.555 g to 500.0 mL of water. Answe

leva [86]

Answer:

0.5188 M or 0.5188 mol/L

Explanation:

Concentration is calculated as molarity, which is the number of moles per litre.

***Molarity is represented by either "M" or "c" depending on your teacher. I will use "c".

The formula for molarity is:

$c = \frac{n}{V}$

n = moles (unit mol)

V = volume (unit L)

Find the molar mass (M) of potassium hydroxide.

$M_{KOH} = \frac{39.098 g}{mol}+\frac{16.000 g}{mol}+\frac{1.008 g}{mol}$

$M_{KOH} = 56.106 \frac{g}{mol}$

Calculate the moles of potassium hydroxide.

$n_{KOH} = \frac{14.555 g}{1}*\frac{1mol}{56.106g}$

$n_{KOH} = 0.25941(9)mol$

Carry one insignificant figure (shown in brackets).

Convert the volume of water to litres.

$V = \frac{500.0mL}{1}*\frac{1L}{1000mL}$

$V = 0.5000L$

Here, carrying an insignificant figure doesn't change the value.

Calculate the concentration.

$c = \frac{n}{V}$

$c = \frac{0.25941(9)mol}{0.5000 L}$

$c = 0.5188(3) \frac{mol}{L}$ <= Keep an insignificant figure for rounding

$c = 0.5188 \frac{mol}{L}$ <= Rounded up

$c = 0.5188M$ <= You use the unit "M" instead of "mol/L"

The concentration of this standard solution is 0.5188 M.

7 0

2 years ago

In the SI system of units, the mole is one of seven base units. It is frequently used in chemical calculations. However, a mole

Irina-Kira [14]

Answer

Do you think that the mole should be considered a base unit in the SI system?

The mole is not a base unit on a par with the six property base units; it cannot be used in significant physical–chemical comparisons until the subscript parameter p in mole-of-Ep has been given a certain “value”."

Explanation:

5 0

2 years ago