Answer:
HCl(aq) + KOH(aq) ⇒ KCl(aq) + H₂O(l)
Explanation:
Hydrochloric acid is an acid because it releases H⁺ in an aqueous solution.
Potassium hydroxide is a base because it releases OH⁻ in an aqueous solution.
When an acid reacts with a base they form a salt and water. This is a neutralization reaction. The neutralization reaction between hydrochloric acid and potassium hydroxide is:
HCl(aq) + KOH(aq) ⇒ KCl(aq) + H₂O(l)
Adding acid and and catching the solution that drains through.
Answer:
I think the answer would be option d.
hope it helps.
Explanation:
The given data is as follows.
T =
= (120 + 273.15)K = 393.15 K,
As it is given that it is an equimolar mixture of n-pentane and isopentane.
So,
= 0.5 and
= 0.5
According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.
(393.15 K) = 9.2 bar
(393.15 K) = 10.5 bar
Hence, we will calculate the partial pressure of each component as follows.

= 
= 4.6 bar
and, 
= 
= 5.25 bar
Therefore, the bubble pressure will be as follows.
P =
= 4.6 bar + 5.25 bar
= 9.85 bar
Now, we will calculate the vapor composition as follows.

= 
= 0.467
and, 
= 
= 0.527
Calculate the dew point as follows.
= 0.5,
= 0.5


= 0.101966
P = 9.807
Composition of the liquid phase is
and its formula is as follows.

= 
= 0.5329

= 
= 0.467
<span>1.00 atm of each gas, in what direction will the system shift to reach equilibrium</span>