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Bond [772]
3 years ago
8

What is the fist to five?

Physics
2 answers:
docker41 [41]3 years ago
6 0

Answer: Fist of Five Voting is a deceivingly simple process you can use to check-in, learn, gain consensus, and/or vote to understand where people ...

Explanation:

sveta [45]3 years ago
6 0

Answer:

Fist to five is a technique for agile

Explanation:

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Hans Eysenck makes a connection between __________ and __________in explaining personality development. A. genetic factors . . .
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The answer is A, genetic factors...conditioning. I just took the test. Good luck!!
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A hypothetical planet has a mass of one-half that of the earth and a radius of twice that of the earth.
Fed [463]
<h2>Option A is the correct answer.</h2>

Explanation:

Acceleration due to gravity

                  g=\frac{GM}{r^2}

         G = 6.67 × 10⁻¹¹ m² kg⁻¹ s⁻²

  Let mass of earth be M and radius of earth be r.

  We have

               g=\frac{GM}{r^2}

Now

         A hypothetical planet has a mass of one-half that of the earth and a radius of twice that of the earth.

       Mass of hypothetical planet, M' = M/2

       Radius of hypothetical planet, r' = 2r

  Substituting

              g'=\frac{GM'}{r'^2}\\\\g'=\frac{G\times \frac{M}{2}}{(2r)^2}\\\\g'=\frac{\frac{GM}{r^2}}{8}\\\\g'=\frac{g}{8}

Option A is the correct answer.

6 0
3 years ago
Predict what happens when glucose levels are high in the humms body
Goryan [66]

Glucose is blood sugar (hyperglycemia) comes from diabeties often, but can occur with other reasons, when glucose is to high someoenes sugar raises. Often this can lead to a diabetic coma, fatigue, vomiting, hospitalization, and even death if serious enough, from to high sugar. Many things can happen after this, and a lot are serious.

on the flip side (hypoglycemia) if sugar gets to low, confusion, fainting, vomiting, and nausea occur, as well as comas, and death if serious enought.

5 0
4 years ago
A material used for electrical wiring must have
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A certain amount of Conductivity
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3 years ago
Objects with masses of 120 kg and a 420 kg are separated by 0.380 m. (a) Find the net gravitational force exerted by these objec
SOVA2 [1]

Answer:

F_{net} = 6.879\times 10^{- 7}\ N

Solution:

As per the question:

Mass of first object, m = 120 kg

Mass of second object, m' = 420 kg

Mass of the third object, M = 69.0 kg

Distance between the m and m', d = 0.380 m

Now,

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m:

F = \frac{GMm}{\frac({d}{2}^{2})}

F = \frac{6.67\times 10^{-11}\times 120\times 0.69}{\frac({0.380}{2}^{2})} = 1.529\times 10^{- 7}\ N

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m':

F = \frac{GMm}{\frac({d}{2}^{2})}

F' = \frac{6.67\times 10^{-11}\times 420\times 0.69}{\frac({0.380}{2}^{2})} = 5.35\times 10^{- 7}\ N

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m and m':

F_{net} = F + F'

F_{net} = 1.529\times 10^{- 7} + 5.35\times 10^{- 7} = 6.879\times 10^{- 7}\ N

6 0
3 years ago
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