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JulijaS [17]
3 years ago
15

The diagram above shows the feedback loop of a home heating system. What will happen in the system if the thermostat breaks whil

e the furnace is off?
A.
The temperature will go above the thermostat temperature.
B.
The whole system will no longer function properly.
C.
The fans will start to blow warm air.
D.
Only the furnace will be affected.
Physics
1 answer:
Neko [114]3 years ago
4 0

Answer:

B

Explanation:

i just did it on study island

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A rope breaks when the tension reaches 205 N. What is the maximum speed at which it can swing a 0.477 kg mass in a circle of rad
jekas [21]

Answer:

Maximum velocity will be 17.651 m /sec

Explanation:

We have given a rope breaks when tension reaches 205 N

Mass m = 0.477 kg

Radius of the circle r = 0.725 m

Tension in the rope is given by

T=\frac{mv^2}{r}

205=\frac{0.477\times v^2}{0.725}

0.477v^2=148.625

v^2=311.5828

v = 17.651 m /sec

8 0
3 years ago
Physics Kinematics question
just olya [345]
An interesting problem, and thanks to the precise heading you put for the question.

We will assume zero air resistance.
We further assume that the angle with vertical is t=53.13 degrees, corresponding to sin(t)=0.8, and therefore cos(t)=0.6.

Given:
angle with vertical, t = 53.13 degrees
sin(t)=0.8; cos(t)=0.6;
air-borne time, T = 20 seconds
initial height, y0 = 800 m

Assume g = -9.81 m/s^2

initial velocity, v m/s (to be determined)

Solution:

(i) Determine initial velocity, v.
initial vertical velocity, vy = vsin(t)=0.8v
Using kinematics equation, 
S(T)=800+(vy)T+(1/2)aT^2 ....(1)  
Where S is height measured from ground.

substitute values in (1):  S(20)=800+(0.8v)T+(-9.81)T^2  =>
v=((1/2)9.81(20^2)-800)/(0.8(20))=72.625 m/s  for T=20 s

(ii) maximum height attained by the bomb
Differentiate (1) with respect to T, and equate to zero to find maximum
dS/dt=(vy)+aT=0 =>
Tmax=-(vy)/a = -0.8*72.625/(-9.81)= 5.9225 s

Maximum height,
Smax
=S(5.9225)
=800+(0.8*122.625)*(5.9225)+(1/2)(-9.81)(5.9225^2)
= 972.0494 m

(iii) Horizontal distance travelled by the bomb while air-borne
Horizontal velocity = vx = vcos(t) = 0.6v = 43.575 m/s
Horizontal distace travelled, Sx = (vx)T = 43.575*20 = 871.5 m

(iv) Velocity of the bomb when it strikes ground
vertical velocity with respect to time
V(T) =vy+aT...................(2)
Substitute values, vy=58.1 m/s, a=-9.81 m/s^2
V(T) = 58.130 + (-9.81)T => 
V(20)=58.130-(9.81)(20) = -138.1 m/s (vertical velocity at strike)

vx = 43.575 m/s (horizontal at strike)
resultant velocity = sqrt(43.575^2+(-138.1)^2) = 144.812 m/s  (magnitude)
in direction theta = atan(43.575,138.1) 
= 17.5 degrees with the vertical, downward and forward. (direction)
4 0
3 years ago
Which change in an abiotic factor causes coral bleaching? a. increased salinity b. decreased salinity c. decreased turbidity d.
Sedbober [7]

The answer is <u>"d. increased temperature".</u>


At the point when corals are stressed by changes in conditions, for example, temperature, light, or supplements, they remove the symbiotic algae living in their tissues, making them turn totally white. Hotter water temperatures can result in coral bleaching. At the point when water is too warm, corals will oust the algae living in their tissues, making the coral turn totally white. This is known as coral bleaching.  

When a coral blanches, it isn't dead. Corals can endure a bleaching occasion, yet they are under more pressure and are liable to mortality.

7 0
3 years ago
Read 2 more answers
A stone whirled at the end of the a rope 30cm long, makes 10 complete resolution in 2 seconds Find: A. The angular velocity in r
lord [1]

Answers:

A: Angular velocity \omega=31.40 \frac{r a d}{s}

B: Linear velocity v=9.42 \frac{m}{s}

C: Linear Distance d=47.1 \mathrm{m}

Given:

Radius of the rope r=30cm=0.3m

Angular distance\Delta \theta=10 revolutions

Time taken t=2seconds

To find:

A: Angular velocity in radians

B: Linear speed

C: Distance covered in 5 seconds

<u>Step by Step Explanations:</u>

Solution:

A: Angular velocity in radians;

According to the formula, Angular velocity can be calculated as

Angular Velocity = angular distance/ time

\omega=\Delta \theta / \Delta t

Where \omega=Angular velocity

\Delta \theta=Angular distance=10 revolutions

Changing revolutions to radians multiply with 2 \pi, so that we get

=10 \times 2 \pi

=10 \times 2(3.14)  

=62.80 rad/rev

\Delta t =Change in time

Substitute the known values in the above equation we get

\omega=62.80 / 2  

\omega=31.40 \frac{r a d}{s}

B. Linear speed of the rope;

As per the formula

Linear speed = angular speed × radius

v=\omega \times r  

Where \omega=Angular velocity

v=Linear speed of the rope

r=Radius of the rope

Substitute the known values in the above equation we get

v=31.40 \times 0.30

v=9.42 \frac{m}{s}

C. Dsitance covered in 5 seconds;

Linear distance = linear speed × time

d=v \times t

Where d= Linear distance of the rope

v=Linear speed of the rope

t=Time taken

Substitute the known values in the above equation we get

d=9.42 \times 5

d=47.1 \mathrm{m}

Result:

Thus A: Angular velocity of the rope \omega=31.40 \frac{r a d}{s}

B Linear speed of the rope v=9.42 \frac{m}{s}

C: Distance covered in 5 seconds d=47.1 \mathrm{m}

6 0
3 years ago
In what scenario might a red ball appear black?
zhuklara [117]
A scenario a red ball might appear black is when there is a shadow in front of it.or when the ball is in a dark place.
3 0
3 years ago
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