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Aleksandr [31]
3 years ago
11

In this experiment, the ______ was intentionally manipulated. This was the independent variable.

Physics
1 answer:
Marizza181 [45]3 years ago
3 0

Answer:

Fan speed

Explanation:

because is the dependent variable

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they play hide and seek with me and im always the seeker U-U

Explanation:

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Which lens combination is used to treat presbyopia ~ ​
abruzzese [7]

Answer:

People with presbyopia require a convex lens for reading glasses; specialized preparations of convex lenses usually require the services of an optometrist

8 0
2 years ago
A jet plane is cruising at 310 m/s when suddenly the pilot turns the engines up to full throttle. after traveling 4.0 km , the j
Inessa [10]
For this problem, we would be using the formula: Vf^2 = Vi^2 + 2ad 
where:
Vf = 400m/s 
Vi = 300m/s 
a = ? 
d = 4.0km 
= 4000m 

400^2 = 300^2 + 2a4000 
a = [ 160000 - 90000 ] / 8000 
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rounding it off to 2 significant figures, will give us 8.8 m/s^2.
4 0
4 years ago
What is the velocity of an electron that has a de Broglie wavelength approximately the length of a chemical bond? Assume this le
melomori [17]

Answer : The velocity of an electron is, 6.1\times 10^{6}m/s

Explanation :

According to de-Broglie, the expression for wavelength is,

\lambda=\frac{h}{p}

and,

p=mv

where,  

p = momentum, m = mass, v = velocity

So, the formula will be:

\lambda=\frac{h}{mv}       .............(1)

where,

h = Planck's constant = 6.626\times 10^{-34}Js

\lambda = wavelength  = 1.2\times 10^{-10}m

m = mass  of electron = 9.11\times 10^{-31}kg

v = velocity of electron = ?

Now put all the given values in formula 1, we get:

1.2\times 10^{-10}m=\frac{6.626\times 10^{-34}Js}{(9.11\times 10^{-31}kg)\times v}

v=6.1\times 10^{6}m/s

Thus, the velocity of an electron is, 6.1\times 10^{6}m/s

6 0
4 years ago
Learning Goal: To be able to calculate work done by a constant force directed at different angles relative to displacement
svlad2 [7]

Answer:

Woke done, W = 4156.92 Joules

Explanation:

The work done by the force can be calculated as :

W=F\times s

W=Fs\ cos\theta

\theta is the angle between force and the displacement

It is assumed to find the work done for the given parameters i.e.

Force, F = 30 N

Distance travelled, s = 160 m

Angle between force and displacement, \theta=30

Work done is given by :

W=Fs\ cos\theta

W=30\times 160\ cos(30)

W = 4156.92 Joules

So, the work done by the object is 4156.92 Joules. Hence, this is the required solution.

5 0
3 years ago
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