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Andreas93 [3]
3 years ago
6

The concentration of HCl can be determined by titration with a primary standard such as Na2CO3 (sodium carbonate). The titration

reaction is CO3(2-) + 2H+ ---> H2O + CO2 What is the concentration of HCl if 35.7 mL of HCl was needed to to react with 0.521 g of Na2CO3 to reach the end point?
Chemistry
2 answers:
Lynna [10]3 years ago
8 0

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Masteriza [31]3 years ago
4 0

Answer:

The concentration of HCl is 0.275 M

Explanation:

<u>Step 1:</u> Data given

Mass of Na2CO3 = 0.521 grams

Molar mass of Na2CO3 = 105.99 g/mol

Volume of HCl = 35.7 mL

<u>Step 2: </u>The balanced equation:

2HCl + Na2CO3 → 2NaCl + CO2 + H2O

CO3(2-) + 2H+ ---> H2O + CO2

<u>Step 3</u>: Calculate moles of Na2CO3

Moles Na2CO3 = mass Na2CO3 / Molar mass Na2CO3

Moles Na2CO3 = 0.521 grams / 105.99 g/mol

Moles Na2CO3 = 0.0049 moles

<u>Step 4:</u> Calculate moles of HCl

For 1 mol of Na2CO3 consumed, we need 2 moles of HCl

moles of HCL = 2 * 0.0049 = 0.0098 moles HCl

<u>Step 5:</u> Calculate molarity of HCl

Molarity = number of moles of HCl / Volume (liters)

Molarity = 0.0098 moles / 0.0357 L

Molarity = 0.275 M

The concentration of HCl is 0.275 M

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In this case, the only source of hydrogen is in the 6 molecules of water, therefore, the atoms of hydrogen, by applying stoichiometry with the Avogadro's number is:

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