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Andre45 [30]
2 years ago
13

Can energy be calculated?

Physics
2 answers:
Rus_ich [418]2 years ago
7 0

Answer:

Energy CANNOT be calculated

Explanation:

Afina-wow [57]2 years ago
4 0

Answer:

NO

Explanation:

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An atom of sodium (Na) gives up an electron to chlorine (Cl) to form table salt. What type of bond is this?
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Your answer will be C!~
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Examine the scenario.
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The electrons in the positive object are attracted to the negatively charged object. Some of the electrons move from the positive object to the negative object.

an example of this is lightning because the positive electrons on/in the earth are attracted to the negative electrons in the clouds and sky so the positive move to the negative charge.

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Listed in the Item Bank are individual steps that need to be ordered. To find out more information about steps, some have more d
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radio

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8 0
2 years ago
QUESTION 4.
n200080 [17]

Answer:

Follows are the solution to this question:

Explanation:

Please find the correct question in the attachment file.

Let:

\overrightarrow{R}= R_i\hat{i}+R_j\hat{j}+R_k\hat{k}\\\\\overrightarrow{S}= S_i\hat{i}+S_j\hat{j}+S_k\hat{k}\\\\

Calculating the value of  \overrightarrow{R} \times \overrightarrow{S}:

\to \left | \begin{array}{ccc}\hat{i}&\hat{j}&\hat{K}\\R_i&R_j&R_k\\S_i&S_j&S_k\end{array}\right | = \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j]

Calculating the value of \overrightarrow{R}  \cdot (\overrightarrow{R} \times \overrightarrow{S}):

\to (R_i\hat{i}+R_j\hat{j}+R_k\hat{k}) \cdot ( \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j])

by solving this value it is equal to 0.

8 0
2 years ago
A straight wire that is 0.60 m long is carrying a current of 2.0 A. It is placed in a uniform magnetic field of strength 0.30 T.
Degger [83]

Answer:

The angle the wire make with respect to the magnetic field is 30°

Explanation:

It is given that,

Length of straight wire, L = 0.6 m

Current carrying by the wire, I = 2 A

Magnetic field, B = 0.3 T

Force experienced by the wire, F = 0.18 N

Let θ be the angle the wire make with respect to the magnetic field. Magnetic force is given by :

F=ILB\ sin\theta

\theta=sin^{-1}(\dfrac{F}{ILB})

\theta=sin^{-1}(\dfrac{0.18\ N}{2\ A\times 0.6\times 0.3\ T})

\theta=30^{\circ}

So, the angle the wire make with respect to the magnetic field is 30°. Hence, this is the required solution.

5 0
2 years ago
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