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Vlad [161]
3 years ago
14

According to le Chatelier’s principle, when a change is introduced into a system in chemical equilibrium, the equilibrium shifts

_____.
A. To the forward reaction
B. To the reverse reaction
C. In the direction that relives the change
D. In the direction that requires the most energy
Physics
2 answers:
Cloud [144]3 years ago
7 0
The answer is C
Because equilibrium means equal
Neko [114]3 years ago
5 0

IN THE DIRECTION THAT RELIVES THE CHANGE - C

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What's the momentum (in kg-m/s) of a cannonball with a mass of 21 moving with a velocity of 25 m/s?
lbvjy [14]
P=mv
P=21*25=525 kg*m/s
8 0
3 years ago
Explain what differentiates the Earth’s crust and lithosphere.
Allisa [31]

Answer:

What is the difference between the crust and lithosphere? The crust (whether continental or oceanic) is the thin layer of distinctive chemical composition overlying the ultramafic upper mantle. ... The lithosphere is the rigid outer layer of the Earth required by plate tectonic theory.

Explanation:

Hope this helps!

4 0
3 years ago
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A bicycle rider traveling east at 10 km/hr sees a blue car pass her appearing to travel west at 50 km/hr. What is the blue car's
BigorU [14]

Answer:

v_{bR} = 25 km/h towards west

Explanation:

As we know that the speed of the blue car as appear to the bicycle rider is given as

v_{bc} = 50 km/h towards west

also it is given that bicycle is moving at speed of 10 km/h towards East

so here we have

v_{bc} = v_b - v_c

so we have

v_b = v_{bc} + v_c

v_b = -50 + 10 = 40 km/h towards west

now speed of the red car is given as 15 km/h towards west

so here the relative speed of blue car with respect to red car is given as

v_{bR} = v_b - v_R

v_{bR} = 40 - 15 = 25 km/h towards west

8 0
3 years ago
A point moves on the x-axis in such a way that its velocity at time t (t > 0) is given by v=ln t/t . At what value of t does
Olenka [21]

Answer:

Explanation:

Given

Velocity of point is given by v=\frac{\ln t}{t}

To get maximum or minimum velocity differentiate v w.r.t t

\frac{\mathrm{d} v}{\mathrm{d} t}=\frac{\frac{1}{t}\times t-1\times \ln(t)}{t^2}

so 1-\ln (t) should be equal to zero

\ln (t)=1

t=e

i.e. t=2.718\ s

5 0
3 years ago
A toy rocket launcher can project a toy rocket at a speed as high as 35.0 m/s.
Anestetic [448]

Answer:

(a) 62.5 m

(b) 7.14 s

Explanation:

initial speed, u = 35 m/s

g = 9.8 m/s^2

(a) Let the rocket raises upto height h and at maximum height the speed is zero.

Use third equation of motion

v^{2}=u^{2}+2as

0^{2}=35^{2}- 2 \times 9.8 \times h

h = 62.5 m

Thus, the rocket goes upto a height of 62.5 m.

(b) Let the rocket takes time t to reach to maximum height.

By use of first equation of motion

v = u + at

0 = 35 - 9.8 t

t = 3.57 s

The total time spent by the rocket in air = 2 t = 2 x 3.57 = 7.14 second.

8 0
3 years ago
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