Answer:
2.9 m/s
Explanation:
Momentum will be conserved
Speed of the ball just before collision is
v = √2gh = √(2(9.8)(0.8)) = 3.96 m/s
The initial momentum is 1.3(3.96) = 5.15 kg•m/s
The block takes away momentum of 0.6(2.2) = 1.32 kg•m/s
Leaving the ball with momentum of 5.15 - 1.32 = 3.83 kg•m/s
vf(ball) = 3.83 / 1.3 = 2.946... ≈ 2.9 m/s
¡Hellow!
For this problem, lets recabe information:
v (Velocity) = 10 m/s
a (Aceleration) = 1 m/s²
t (Time) = 1/4 min = 25 s
d (Distance) = ?
v' (Final velocity) = ?
First, for calculate distance, lets applicate formula:

Lets replace according we information and let's resolve it:
d = 10 m/s * 25 s + (1 m/s² * (25 s)²) * 0,5
d = 250 m + (625 m) * 0,5
d = 2,5 m + 312,5 m
d = 314 meters.
Now, for calculate final speed, lets applicate formula:

Lets replace according we information and let's resolve it:
v' = 10 m/s + 1 m/s² * 25 s
v' = 10 m/s + 25 m/s
v' = 35 m/s
¿Good Luck?
Att: That guy who use the "ñ".
Ice, which is the solid state of water, the liquid
It is harder to push a box with groceries in it because the mass is weighing the box down. Which makes it harder to push