Answer:
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Explanation:
Answer:
2.18 grams of Br2 reacts to produce 3.25 grams of KBr
Explanation:
The balanced equation is
2 KI + Br2 → 2 KBr + I2
2 moles of KI and 1 mole of Br2 reacts to produce two molecules of KBr
Mass of two moles of KI = 2 * 166 grams
Mass of one mole of Br2 = 159.808 grams
Mass of two moles of KBr = 2* 119 grams
Thus, 159.808 grams of Br2 reacts to produce 2* 119 grams of KBr
2.18 grams of Br2 reacts to produce {(2* 119)/ 159.808} * 2.18 grams of KBr
2.18 grams of Br2 reacts to produce 3.25 grams of KBr
The mass of water is determined by calculating the difference in mass of the sample before and after the heating.
Mass of water = 3.677 - 2.216
Mass of water = 1.461 g
Moles of water = 1.461 / 18 = 0.0812
Mass of NaC₂H₃O₂ = 2.216 g
Moles of NaC₂H₃O₂ = 2.216 / 82 = 0.0270
Molar ratio = 0.0812 / 0.0270 = 3.00
Therefore, there are 3 moles of water for every mole of NaC₂H₃O₂
There are 70 atoms in 5CaC12