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alina1380 [7]
3 years ago
14

A beaker contains 100.0 mL of pure water. A second beaker contains 100.0 mL of seawater. The two beakers are left side by side o

n a lab bench for one week. At the end of the week, the liquid level in both beakers has decreased. However, the level has decreased more in one of the beakers than in the other. Which one and why?
Chemistry
1 answer:
shusha [124]3 years ago
3 0

Answer: The beaker in which water level has decreased more is the one that contains pure water.

Explanation: Even when water is not heated it can evaporate, that is because molecules move at different speed and those that are closer to surface can break the gass pressure and scape as water vapor.

The movement of molecules of water can be affected by the presence of solutes (salts or other soluble compounds) and increase the evaporation temperature. For this particular case, molecules of salt atract the water molecules (remember salt has ions and water is a dipole with partial charges) and do not let the water move freely which avoid them to scape to the surface.

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A solution of hydrochloric acid (HCl, 25.00 mL) was titrated to completion with 34.55 mL of 0.1020 M sodium hydroxide. What was
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Answer:

0.1410 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nA) = 1

The mole ratio of the base, NaOH (nB) = 1

Next, the data obtained from the question. This include:

Volume of acid, HCl (Va) = 25 mL

Volume of base, NaOH (Vb) = 34.55 mL

Concentration of base, NaOH (Cb) = 0.1020 M

Concentration of acid, HCl (Ca) =?

CaVa / CbVb = nA/nB

Ca × 25 / 0.1020 × 34.55 = 1/1

Ca × 25 / 3.5241 = 1/1

Cross multiply

Ca × 25 = 3.5241 × 1

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Divide both side by 25

Ca = 3.5241 / 25

Ca = 0.1410 M

Therefore, the concentration of the acid, HCl is 0.1410 M

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