Explanation:
It is given that,
length of steel wire, l = 0.75 m
Mass of the wire, m = 12 g = 0.012 kg
Fundamental frequency, f = 120 Hz
We need to find the mass of the anvil (m'). The fundamental frequency is given by :
v is the speed of the mass
Speed is given by :
is the mass per unit length,
T is the tension in the wire,
T = 518.4 N
Tension in the wire, T = m' g
m' = 52.89 kg
So, the mass of the anvil is 52.89 kg. Hence, this is the required solution.
Answer:
d) 1.2 mT
Explanation:
Here we want to find the magnitude of the magnetic field at a distance of 2.5 mm from the axis of the coaxial cable.
First of all, we observe that:
- The internal cylindrical conductor of radius 2 mm can be treated as a conductive wire placed at the axis of the cable, since here we are analyzing the field outside the radius of the conductor. The current flowing in this conductor is
I = 15 A
- The external conductor, of radius between 3 mm and 3.5 mm, does not contribute to the field at r = 2.5 mm, since 2.5 mm is situated before the inner shell of the conductor (at 3 mm).
Therefore, the net magnetic field is just given by the internal conductor. The magnetic field produced by a wire is given by
where
is the vacuum permeability
I = 15 A is the current in the conductor
r = 2.5 mm = 0.0025 m is the distance from the axis at which we want to calculate the field
Substituting, we find: