The bouncy ball experiences the greater momentum change.
To understand why, you need to remember that momentum is actually
a vector quantity ... it has a size AND it has a direction too.
The putty and the ball have the same mass, and you throw them
with the same speed. So, on the way from your hand to the wall,
they both have the same momentum.
Call it " M in the direction toward the wall ".
After they both hit the wall:
-- The putty has zero momentum.
Its momentum changed by an amount of M .
-- The ball has momentum of " M in the direction away from the wall ".
Its momentum changed by an amount of 2M .
The total displacement is 4.0 m east.
Answer:
I think it would most likely be 2... but not so sureee
Answer:
The radius of the wetter area expands at a rate of 
milimeters per second when radius is 150 milimeters.
Explanation:
From Geometry we remember that area of a circle is described by this expression:
(Eq. 1)
Where:
- Radius of the circle, measured in milimeters.
- Area of the circle, measured in square milimeters.
Then, the rate of change of the area in time is derived by concept of rate of change, that is:
(Eq. 2)
Where:
- Rate of change of radius in time, measured in milimeters per second.
- Rate of change of area in time, measured in square milimeters per second.
Now the rate of change of radius in time is cleared within equation above:
If we know that 
and 
, then the rate of change of radius in time is:
![\frac{dr}{dt} = \left[\frac{1}{2\pi\cdot (150\,m)} \right] \cdot \left(4\,\frac{mm^{2}}{s} \right)](https://tex.z-dn.net/?f=%5Cfrac%7Bdr%7D%7Bdt%7D%20%3D%20%5Cleft%5B%5Cfrac%7B1%7D%7B2%5Cpi%5Ccdot%20%28150%5C%2Cm%29%7D%20%5Cright%5D%20%5Ccdot%20%5Cleft%284%5C%2C%5Cfrac%7Bmm%5E%7B2%7D%7D%7Bs%7D%20%5Cright%29)
The radius of the wetter area expands at a rate of milimeters per second when radius is 150 milimeters.
