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BaLLatris [955]
4 years ago
12

What is the acceleration of the car at segment C? 30 m/s2, –30 m/s2, 40 m/s2, or –40 m/s2

Physics
2 answers:
nadezda [96]4 years ago
8 0

Answer:

wait i did this before

Explanation:

Varvara68 [4.7K]4 years ago
3 0

Answer:

-30 m/s

Explanation:

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A rock is dropped into a well. If you hear a splash 14 seconds later what was its speed
grigory [225]

Answer:

14 seconds

Explanation:

because you dropped it and it takes 14 seconds

4 0
3 years ago
Here is a "formula" for building a model airplane: 1 body + 2 wings + 4 jet engines + 1 tailpiece → 1 model airplane if a hobbyi
WINSTONCH [101]
Your answer is 44 wings

3 0
4 years ago
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Suppose a parachutist lands on a high-voltage wire and grabs the wire as she prepares to be rescued.(a) Will she be electrocuted
Kamila [148]

Suppose a parachutist lands on a high-voltage wire and grabs the wire as she prepares to be rescued, she will not be electrocuted.

<h3>What is Voltage?</h3>

This is referred to as the difference in electric potential between two points or the work done which is needed per unit to move a charge between two points in a circuit.

If she grabs the wire as she prepares to be rescued, she will not be electrocuted because the net electrical potential will be 0.

In a situation where the wire breaks as she holds on to it then she will be electrocuted.

Read more about Voltage here  brainly.com/question/1176850

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6 0
2 years ago
What effect does an unbalanced force have on an object?
Taya2010 [7]
This changes it's state of motion (or lack of).
3 0
4 years ago
A cosmic ray travels 60.0 km through the earth's atmosphere in 500 μs , as measured by experimenters on the ground. You may want
zavuch27 [327]

Answer:

t' = 458.26 μs

Explanation:

given,

distance traveled by the cosmic ray = 60 Km

time = 500 μs

time taken for the journey according to cosmic ray = ?

now,

 v =\dfrac{distance}{time}

 v =\dfrac{60\times 10^3}{500\times 10^{-6}}

      v = 1.2 x 10⁸ m/s

according to time dilation formula

t' = t\sqrt{1-\dfrac{v^2}{c^2}}

t' = 500\sqrt{1-\dfrac{(1.2\times 10^8)^2}{(3\times 10^8)^2}}

     t' = 500 x 0.9165

    t' = 458.26 μs

6 0
3 years ago
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