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3 years ago

Alkanes are hydrocarbons that contain what type of bonds

Chemistry

2 answers:

horsena [70]3 years ago

8 0

Alkanes, Alkenes, Aromatic, Hydrocarbons and Isomers

olga2289 [7]3 years ago

3 0

Carbon carbon triple bonds

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A copper coin with a mass of 6.30 grams changes temperature in the sunshine from 20.0°C to 32.0°C. How much energy is transferre

Mariana [72]

The energy transferred is 28.5 j

calculation

energy is calculate MCΔT formula where,

M(mass)= 6.30 grams

C(specific heat capacity)= 0.377 j/g

ΔT(change in temperature)= 32.0c- 20 c= 12 c

Energy is therefore= 6.30 g x 0.377 j/g /c x 12 c =28.5 j

8 0

4 years ago

Read 2 more answers

The strongest base that can exist in a solution in appreciable concentration is the conjugate base of the solvent.

MArishka [77]

Answer:

a. True

Explanation:

From the basic concepts of acids and bases, we know that when a base accepts a hydrogen ion (H⁺), it forms a conjugate acid which can accept again the H⁺ ion:

B⁻ + H₂O ⇆ BH + OH⁻

The stronger the base, the weaker the conjugate base. Thus, as more strength has a base, lesser strength will have the conjugate base (it will not be able to accept again the H⁺ ion). For example, when water (H₂O) loses its H⁺ , it forms the conjugate base OH⁻. So, OH⁻ is the stronger base that can exist in an aqueous solution.

H₂O ⇆ H⁺ + OH⁻

In fact, strong bases are hydroxides, such as NaOH or KOH.

6 0

3 years ago

Calculate the final temperature of the system: A 50.0 gram sample of water initially at 100 °C and a 100 gram sample initially a

katrin2010 [14]

Answer:

The final temperature of the system is 42.46°C.

Explanation:

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c\times (T_f-T_1)=-(m_2\times c\times (T_f-T_2))$

where,

c = specific heat of water= $4.18J/g^oC$

$m_1$ = mass of water sample with 100 °C= 50.0 g

$m_2$ = mass of water sample with 13.7 °C= 100.0 g

$T_f$ = final temperature of system

$T_1$ = initial temperature of 50 g of water sample= $100^oC$

$T_2$ = initial temperature of 100 g of water = $13.7^oC$

Now put all the given values in the given formula, we get

$50.0 g\times 4.184 J/g^oC\times (T_f-100^oC)=-(100 g\times 4.184 J/g^oC\times (T_f-13.7^oC))$

$T_f=42.46^oC$

The final temperature of the system is 42.46°C.

5 0

4 years ago

If a tube contains 2.0oz of sunscreen, how many kilograms of benzyl salicylate are needed to manufacture 325 tubes of sunscreen

Vadim26 [7]

Answer:

Now it is given here that there are 325 tubes that are manufactured for sunscreen. And we also know that the percentage of sunscreen in benzyl salicylate is 2.5% here in one tube we have 2 Oz of sunscreen.

Explanation:

So sunscreen in 325 tubes will be 2 x 325= 650 Oz. Since we know the amount of sunscreen in 325 tubes the amount of Benzyl salicylate in all 325 tubes will be 650 x 0.025 = 16.25 Oz

Now this can be converted into kg as 0.46 kg.

4 0

3 years ago

A book is pushed off the edge of a table. At what point during the fall will the potential and kinetic energy be equal?

vfiekz [6]

Answer:

KE = PE at half the table Height:

Explanation

AT ANY POINT IN THE BOOK'S FALL,

TOTAL E = PE +KE

THE TOTAL E IS CONSTANT

Before the book is pushed off, the total energy is potential

TOT E=PE =MGH

BEFORE THE BOOK HITS THE GROUND, THE TOTAL E IS KINETIC

TOT=KE = MVXV/2

WHEN KE = PE

KE+PE = MGH (STARTING ENERGY SINCE E IS CONSERVED)

OR PE+ PE = MGH

OR MGH' + MGH' =MGH

OR 2H' =H

H' (NEW HEIGHT) =H/2

5 0

3 years ago