5 mols = 100 grams
1 mol = 100/5
1 mol = 20 grams.
Most likely d because water is being used for energy, therefore releasing water vapo. Also by process of elimination, that´s the one that makes sense lol.
Answer:
a, b, c, d
Explanation:
Rutherford’ atomic model is based on the gold foil experiment. In this experiment, beam of alpha rays was bombarded on thin gold foil. He observed that:
Most of the alpha particles passed through thin foil without any deflection.
Few alpha particles deflected by an angle of 90o.
Based on observation, Rutherford concluded that majority of the space inside the atom is empty.
He explained defection of few alpha particles by assuming that most of the mass is concentrated at the nucleus and positively charged.
Therefore, among given, the correct statements are:
The atom contains a positively charged nucleus.
Positive charge is condensed in one location within the atom.
The majority of the space inside the atom is empty space
The mass of an atom is concentrated at the nucleus
Therefore, the correct options are:
a, b, c, d
Answer:
See explaination
Explanation:
1) Pb(NO3)2 => Pb2+ + 2 NO3-
[Pb2+] = [Pb(NO3)2] = 7.56 mM = 7.56 x 10-3 M
Pb(IO3)2 <=> Pb2+ + 2 IO3-
Ksp = [Pb2+][IO3-]2 = 2.5 x 10-13
7.56 x 10-3 x [IO3-]2 = 2.5 x 10-13
[IO3-] = 5.75 x 10-6 M ≈ 5.8 x 10-6 M
(2) [Pb2+] = 1.7 x 10-6 M
Ksp = [Pb2+][IO3-]2 = 2.5 x 10-13
1.7 x 10-6 x [IO3-]2 = 2.5 x 10-13
[IO3-] = 3.83 x 10-4 M
[IO3-]from Pb(IO3)2 = 2 x [Pb2+]
= 2 x 1.7 x 10-6 = 3.4 x 10-6 M
[IO3-]from NaIO3 = [IO3-] - [IO3-]from Pb(IO3)2
= 3.83 x 10-4 - 3.4 x 10-6
= 3.80 x 10-4 M
NaIO3 => Na+ + IO3-
[NaIO3] = [IO3-]from NaIO3
= 3.80 x 10-4 M ≈ 3.8 x 10-4 M
