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Anton [14]
3 years ago
5

A race car travels 765 km around a circular sprint track of radius 1.263 km. How many times did it go around the track?

Physics
1 answer:
sladkih [1.3K]3 years ago
4 0

Answer:

It will go 96 times around the track.

Explanation:

Given that,

Distance covered by the race car, d = 765 km

Radius of the circular sprint track, r = 1.263 km

Let n times did it go around the track. It is given by :

n=\dfrac{d}{C}

C is the circumference of the circular path, C=2\pi r

n=\dfrac{d}{2\pi r}

n=\dfrac{765}{2\pi \times 1.263}

n=96.4

Approximately, n = 96

So, it will go 96 times around the track. Hence, this is the required solution.

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Which of the following is not a transverse wave?A) soundB) lightC) radioD) all of theseE) none of these
quester [9]
The answer is light, because a transverse wave is a wave vibrating at right angles to the direction of its propagation
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3 years ago
The initial concentration of N2O4 is 0.45M The system is heated and allowed to reach equilibrium. At equilibrium concentration o
Damm [24]

Answer : The value of equilibrium constant K_c for the following reaction will be, 2.4

Explanation :  Given,

Initial concentration of N_2O_4 = 0.45 M

Equilibrium concentration of NO_2 = 0.30 M

K_c is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The given balanced equilibrium reaction is,

N_2O_4(g)\rightleftharpoons 2NO_2(g)

As we know that the concentrations of pure solids are constant that means they do not change. Thus, they are not included in the equilibrium expression.

Actual concentration of NO_2 at equilibrium = 2\times 0.30M=0.6M

Concentration of N_2O_4 at equilibrium = [N_2O_4]-[NO_2]=0.45-0.30=0.15M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

Now put all the given values in this expression, we get :

K_c=\frac{(0.6)^2}{(0.15)}

K_c=2.4

Therefore, the value of equilibrium constant K_c for the following reaction will be, 2.4

3 0
3 years ago
Are rubber bands and metal springs the same? Explain your reasoning​
d1i1m1o1n [39]

Answer:

No, they are not because when you stretch the rubber band you are deforming it but with the spring it is made to go up and down.

Explanation:

4 0
3 years ago
Read 2 more answers
Sapting Leng You have a string with a mass of 13.7 q. You stretch the string with a force of 8.39 N, giving it a length of 1.87
marshall27 [118]

Answer:

a)  \lambda=0.935\ \textup{m}

b) f=36.19\approx 36\ \textup{Hz}

Explanation:

Given:

String vibrates transversely fourth dynamic, thus n = 4

mass of the string, m = 13.7 g = 13.7 × 10⁻¹³ kg

Tension in the string, T = 8.39 N

Length of the string, L = 1.87 m

a) we know

L= n\frac{\lambda}{2}

where,

\lambda = wavelength

on substituting the values, we get

1.87= 4\times \frac{\lambda}{2}

or

\lambda=0.935\ \textup{m}

b) Speed of the wave (v) in the string is given as:

v =f\lambda

also,

v=\sqrt\frac{T}{(\frac{m}{L})}

equating both the formula for 'v' we get,

f\lambda=\sqrt\frac{T}{(\frac{m}{L})}

on substituting the values, we get

f\times 0.935=\sqrt\frac{8.39}{(\frac{13.7\times 10^{3}}{1.87})}

or

f=\frac{33.84}{0.935}

or

f=36.19\approx 36\ \textup{Hz}

5 0
3 years ago
How you can change the state of matter of the substance in the container.
Deffense [45]

Answer:

Change in the shape size volume and state of a substance

When a solid is heated, it turns into a liquid. As a liquid, a substance has a fixed volume, but its shape changes to fill the shape of its container. For instance, a glass of water is the liquid state of water. ... Gas expands to fill the shape and volume of its container.

Explanation:

8 0
3 years ago
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