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Anton [14]
3 years ago
5

A race car travels 765 km around a circular sprint track of radius 1.263 km. How many times did it go around the track?

Physics
1 answer:
sladkih [1.3K]3 years ago
4 0

Answer:

It will go 96 times around the track.

Explanation:

Given that,

Distance covered by the race car, d = 765 km

Radius of the circular sprint track, r = 1.263 km

Let n times did it go around the track. It is given by :

n=\dfrac{d}{C}

C is the circumference of the circular path, C=2\pi r

n=\dfrac{d}{2\pi r}

n=\dfrac{765}{2\pi \times 1.263}

n=96.4

Approximately, n = 96

So, it will go 96 times around the track. Hence, this is the required solution.

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Find the speed of a satellite in geostationary orbit.
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Answer:

A geostationary orbit can be achieved only at an altitude very close to 35,786 kilometres (22,236 miles) and directly above the equator. This equates to an orbital speed of 3.07 kilometres per second (1.91 miles per second) and an orbital period of 1,436 minutes, one sidereal day

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2 years ago
a wave in which particles of the medium vibrate at right angles to the direction that the wave travels is called?
Vera_Pavlovna [14]

Explanation:

Longitudinal waves are waves in which the vibration of the medium is parallel to the direction the wave travels and displacement of the medium is in the same (or opposite) direction of the wave propagation. Mechanical longitudinal waves are also called compressional or compression waves, because they produce compression and rarefaction when traveling through a medium, and pressure waves, because they produce increases and decreases in pressure. 

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3 years ago
Read 2 more answers
Chris shoots an arrow up into the air. The height of the arrow is given by the function h(t) = - 16t2 + 32t + 26 where t is the
seropon [69]

Answer:

The maximum height of the arrow is 42 (and the units given for the height)

Explanation:

Everything is easier if you make a graph, you can give values to t and replace that values in the function, for example:

When t=0

h(0)=-16(0^{2})+32(0)+26

h(0)=26

If you give some values to t you can see how the trajectory of the arrow is (please look the graphic below)

Now, to find the maximum you have to find the derivative of the function that describes the height of the arrow:

h(t)=-16t^{2}+32t+26

h'(t)=-32t+32

Then you have to take the derivative, and equals to zero to find t:

-32t+32=0

-32t=32

t=1

That is in the time of 1 second the arrow has its maximum height.

Now you have to replace this value in the original function, to find the height of the arrow:

h(1)=-16(1^{2})+32(1)+26

h(1)=-16+32+36

h(1)=42

4 0
3 years ago
During light activity, a 70-kg person may generate 200 kcal
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Answer:

2.75387\ ^{\circ}

Explanation:

m = Mass of person = 70 kg

c = Specific heat of human body = 0.83\ J/kg^{\circ}C

\Delta T = Change in temperature

Time taken is 1 hour

Heat is given by

Q=mc\Delta T\\\Rightarrow \Delta T=\dfrac{Q}{mc}\\\Rightarrow \Delta T=\dfrac{0.8\times 200\times 1}{70\times 0.83}\\\Rightarrow \Delta T=2.75387\ ^{\circ}C

The rise in temperature is 2.75387\ ^{\circ}C

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4 years ago
The transmission of heat requiring the movement of a liquid or a gas is
AysviL [449]

Answer:

convection

Explanation:

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