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mixer [17]
2 years ago
11

The decomposition of ethyl amine, C2H5NH2, occurs according to the reaction: C2H5NH2(g)⟶C2H4(g)+NH3(g) At 85∘C, the rate constan

t for the reaction is 2.5 x 10-1 s-1. What is the half-life (in sec) of this reaction?
Chemistry
1 answer:
statuscvo [17]2 years ago
7 0

Answer:

2.772 seconds

Explanation:

Given that;

t1/2 = 0.693/k

Where;

t1/2 = half life of the reaction

k= rate constant

Note that decomposition is a first order reaction since the rate of reaction depends on the concentration of one reactant

t1/2 = 0.693/2.5 x 10-1 s-1

t1/2= 2.772 seconds

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Answer:

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From the ideal gas law we can determine the number of moles that the 2.25 L represent.

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Moles glucose required:

0.093 mol CO₂  x  ( 1 mol C₆H₁₂O₆   / 2 mol CO₂ ) =  0.046 mol C₆H₁₂O₆

The molar mass of glucose is 180.16 g/mol, then the mass required is

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