All categories

3 years ago

Brainliest for correct answer :)

Physics

2 answers:

kiruha [24]3 years ago

8 0

Answer:

Explanation:

melisa1 [442]3 years ago

5 0

Answer:

B- They both have travelled equal distances in 7 minutes

Hope this helps!

You might be interested in

Please Help Conservation of energy

Sonja [21]

Answer:

a principle stating that energy cannot be created or destroyed, but can be altered from one form to another.

Explanation:

8 0

2 years ago

A .140kg baseball traveling 35.0m/s strikes the catchers mit bringing the ball to rest, recoils backward 11.0cm what’s the avera

Juli2301 [7.4K]

Average force applied by the call on the glove = 780 N

Explanation:

mass of baseball=0.140 kg

initial velocity = Vi= 35 m/s

Final velocity=Vf= 0

distance traveled=11 cm= 0.11 m

using the kinematic equation Vf²= Vi²+ 2 a d

where a = acceleration

0²= 35²+ 2 a (0.11)

a=-5568.2 m/s²

Now force is given by F= ma

F= 0.140 (5568.2)

F=-780 N

The negative sign signifies that the force acts in the opposite direction.

so the average force= 780 N

6 0

2 years ago

1. li took 2 } seconds for a car's vclocity to change from 20 m/s to 15 m/s. The mass of the car was 1370 kg. What force was req

Pani-rosa [81]

Answer:

Do you still need help??

Explanation:

3 0

2 years ago

In this first example of constant accelerated motion, we will simply consider a car that is initially traveling along a straight

algol13

Answer:

$v_{f} =25m/s$

Explanation:

Kinematics equation for constant acceleration:

$v_{f} =v_{o} + at=15+2*5=25m/s$

4 0

2 years ago

The body falls in a free fall 11s.Calculate: a) from what height the body of the paddle) what path did it fall during the last s

JulsSmile [24]

Answer:

a) h = 593.50 m

b) h₁₁ = 103 m

c) vf = 107.91 m/s

Explanation:

We will use second equation of motion to find the height:

$h = v_{i}t + (\frac{1}{2})gt^2$

where,

h = height = ?

vi = initial speed = 0 m/s

t = time taken = 11 s

g = 9.81 /s²

Therefore,

$h = (0\ m/s)(11\ s) + (\frac{1}{2})(9.8\ m/s^2)(11\ s)^2\\\\$

h = 593.50 m

For the distance travelled in last second, we first need to find velocity at 10th second by using first equation of motion:

$v_{f} = v_{i} + gt$

where,

vf = final velocity at tenth second = v₁₀ = ?

t = 10 s

vi = 0 m/s

Therefore,

$v_{10} = 0\ m/s + (9.81\ m/s^2)(10\ s)\\\\v_{10} = 98.1\ m/s$

Now, we use the 2nd equation of motion between 10 and 11 seconds to find the height covered during last second:

$h = v_{i}t + (\frac{1}{2})gt^2$

where,

h = height covered during last second = h₁₁ = ?

vi = v₁₀ = 98.1 m/s

t = 1 s

Therefore,

$h_{11} = (98.1\ m/s)(1\ s) + (\frac{1}{2})(9.8\ m/s^2)(1\ s)^2\\\\$

h₁₁ = 103 m

Now, we use first equation of motion for complete motion:

$v_{f} = v_{i} + gt$

where,

vf = final velocity at tenth second = ?

t = 11 s

vi = 0 m/s

Therefore,

$v_{f} = 0\ m/s + (9.81\ m/s^2)(11\ s)$

vf = 107.91 m/s

8 0

3 years ago