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3 years ago

A car starts from rest and accelerates for 5.2 s

Physics

1 answer:

vodomira [7]3 years ago

6 0

Answer:

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Explanation:

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Which force is involved in kicking a ball? 1. Frictional force 2. Pushing force

FrozenT [24]

Answer:

Pushing force

Explanation:

You technically push a ball when kicking it.

7 0

3 years ago

Read 2 more answers

Think back to coulomb's law. two coins with identical charges are placed on a lab table 1.35 m apart.

ziro4ka [17]

The Coulomb’s law is expressed mathematically as:

F = k * q1 * q2 / d^2

Where,

F = force of attraction between 2 particles = 2.0 N

k = Coulomb’s constant = 8.988 * 10^9 N m^2 / C^2

q = charge of the particle

d = distance between the 2 particles = 1.35 m

Since the two coins have identical charges therefore q1 = q2 =q

F = k* q^2 / d^2

2.0 N = (8.988 * 10^9 N m^2 / C^2) * q^2 / (1.35 m)^2

q = 2.01 * 10^-5 C

Therefore each coins have charges equivalent to 2.01 * 10^-5 C.

4 0

4 years ago

Suppose a stream of negatively charged powder was blown through a cylindrical pipe of radius R = 7.5 cm. Assume that the powder

Ipatiy [6.2K]

Answer:

A) $E =\frac{\rho r}{2\epsilon}$

B) $v = 58.7923\times 10^4 V$

Explanation:

a) using Guass law

$\oint E.dA = \frac{q_{enclosed}}{\epsilon_o}$

$EA = \frac{q_{enclosed}}{\epsilon_o}$

$E = \frac{q_{enclosed}}{A \epsilon_o}$

Here $A is = 2\pi rL$

$E = \frac{q_{enclosed}}{(2\pi rL) \epsilon_o}$

Volume charge density is given as

$\rho = \frac{q_{enclosed}}{volume}$

net charge is given as

$q_{enclosed} = \rho \times volume$

therefore $E = \frac{ \rho \times (L\pi r^2)}{(2\pi rL) \epsilon_o}$

$VOLUME = L\pi r^2$

After solving electric field equation we get

$E =\frac{\rho r}{2\epsilon}$

b) electric potential difference is given as

$v_{wall} - v = - \int_{r}^{R} Edr$

$0 - v = - \int_{r}^{R} E dr$

$v = \int_{r}^{R} Edr$

$= \int_{r}^{R} (\frac{\rho r}{2\epsilon}) dr$

$= \frac{\rho}{4\epsilon} (R^2 - r^2)$

at r = 0

$v = \frac{- 3.7 \times 10^{-3} \times 0.075^2}{4\times (8.85\times 10^{-12}}$

$v = 58.7923\times 10^4 V$

7 0

3 years ago

You serve a volleyball with a mass of 1.4 kg. The ball leaves with a speed of 13 m/s. Calculate KE

NemiM [27]

Answer:

118.3 J

Explanation:

Givens:

m = 1.4 kg

V = 13 m/s

Formula for kinetic energy:

KE = (1/2)*(m)*(v)^2

KE = .5*(1.4 kg)*(13 m/s)^2

KE 118.3 J

J = Joules

7 0

3 years ago

How much heat must be added to 4.55 kg of copper to change it from a solid at 1358 K to a liquid at 1358 K? Latent heat of fusio

scoundrel [369]

Answer:

H=9.42 X 10^5 J

Explanation:

Heat required H = Mass of copper x latent heat of fusion of copper

H=4.55 x 20.7×104

H=941850

H=9.42 X 10^5 J

7 0

3 years ago