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Vadim26 [7]
2 years ago
12

What type of chemical agent produces temporary physiological effects, mental effects, or both, which may persist for hours or da

ys after exposure?
Chemistry
1 answer:
myrzilka [38]2 years ago
8 0

Psychochemical may persist for hours or days after exposure.

<h3>Psychochemical </h3>

Chemical substances that have brief, reversible effects on the body or mind are known as psychochemical agents, often known as incapacitating substances. Psychochemical agents have a longer-lasting effect than riot-control chemicals, which only have a few-minute duration. Central nervous system (CNS) stimulants and depressants both fall within the category of psychochemical substances.

Drugs that depress the central nervous system (CNS) prevent the CNS from functioning and prevent information from traveling across neuron synapses. 3-Quinuchdedinyl Benzilate is an illustration of this group of chemicals, and it has an impact on memory, problem-solving, focus, and instruction-listening abilities. Instead of affecting one's ability to think, cannabinoids and phenothiazines cause sleepiness and a lack of motivation. Although 10,000 times more strong than morphine, fenyls are opiates that have a similar effect.

Learn more about Psychochemical here:

brainly.com/question/23693316

#SPJ4

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1(30%). A thin plate black body, insulated at the bottom is placed faced up in a room with wall temperatures of 30 C. Air at 0 C
ch4aika [34]

Explanation:

The given data is as follows.

         Heat transfer coefficient (h) = 12W/m^{2}.C

         Plate temperature (T_{1}) = 30 ^{o}C = 303 K

         Steady state temperature (T_{2}) = ?

Hence, formula applied for steady state is as follows.

       (h \times A \times \Delta T)_{air} = \sigma \times A \times (T^{4}_{1} - T^{4}_{2})_{plate}

Putting the given values into the above formula as follows.

       (h \times A \times \Delta T)_{air} = \sigma \times A \times (T^{4}_{1} - T^{4}_{2})_{plate}

        12 \times (T_{2} - 273) = 5.67 \times 10^{-8} \times [(30 + 273)^{4} - T^{4}_{2}]

                  T_{2} = 282.66 K

                              = (282.66 -273)^{o}C      

                              = 9.66 ^{o}C      

Thus, we can conclude that the steady state temperature will be 9.66 ^{o}C.

3 0
3 years ago
A chemist measures the energy change
Flauer [41]

<u>Answer:</u>

<u>For (1):</u> The correct option is (a)

<u>For (2): </u>The correct option is (a) and 333.6 kJ of heat will be absorbed when 70.9 g of ammonia reacts.

<u>Explanation:</u>

There are 2 types of reactions that are classified based on enthalpy change:

<u>Endothermic reactions:</u> These are the reactions where heat is absorbed by the reaction. The change in enthalpy of the reaction, \Delta H_{rxn} is positive for these reactions.

<u>Exothermic reactions:</u> These are the reactions where heat is released by the reaction. The change in enthalpy of the reaction, \Delta H_{rxn} is negative for these reactions.

  • <u>For (1):</u>

For the given chemical reaction:

2NH_3(g)\rightarrow N_2(g)+3H_2(g);Delta H=160kJ

As the change in enthalpy or heat of the reaction is positive. Thus, the reaction is an endothermic reaction because heat is absorbed by the reaction.

  • <u>For (2):</u>

When ammonia reacts, some amount of heat will be absorbed by the reaction. Thus, we can say the heat will be absorbed.

The number of moles is calculated by using the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

Given mass of ammonia = 70.9 g

Molar mass of ammonia = 17 g/mol

Using equation 1:

\text{Moles of ammonia}=\frac{70.9g}{17g/mol}=4.17mol

By stoichiometry of the reaction:

If 2 mole of ammonia reacts, the heat absorbed is 160 kJ

So, if 4.17 moles of ammonia reacts, the heat absorbed will be = \frac{160kJ}{2mol}\times 4.17mol=333.6kJ

Hence, 333.6 kJ of heat will be absorbed when 70.9 g of ammonia reacts

8 0
3 years ago
3. Given the following equation:
miskamm [114]

Answer:

4.767 grams of KCl are produced from 2.50 g of K and excess Cl2

Explanation:

The balanced equation is

2 K+ Cl2 --->2 KCI

Here the limiting agent is K. Hence, the amount of KCl will be calculated as per the mass of 2.50 gram of K

Mass of one atom/mole of potassium is 39.098 grams

Number of moles is 2.5 grams = \frac{2.5}{39.098} = 0.064

So, 2 moles of K produces 2 moles of KCL

0.064 moles of K will produces 0.064 moles of KCl

Mass of one molecule of KCl is 74.5513 g/mol

Mass of 0.064 moles of KCl is 4.767 grams

4 0
3 years ago
What Phase is water at 120 degrees Celsius?
Rina8888 [55]
At atmospheric pressure water boils at 100 degC.
So the water would be gas/vapor/steam.
4 0
3 years ago
What is the percent-by-mass, %(m/m), concentration of sucrose ( table sugar) in a solution made by dissolving 22.8 g of sucrose
Ede4ka [16]

Answer:

32.6 %

Explanation:

Given data

  • Mass of sucrose (solute): 22.8 grams
  • Mass of water (solvent): 47.1 grams

Step 1: Calculate the mass of the solution

The mass of the solution is equal to the sum of the mass of the solute and the mass of the solvent.

m(solution) = m(solute) + m(solvent)

m(solution) = 22.8 g + 47.1 g

m(solution) = 69.9 g

Step 2: Calculate the percent-by-mass of sucrose in the solution

We will use the following expression.

\% m/m = \frac{mass\ of\ sucrose}{mass\ of\ solution} \times 100\% = \frac{22.8g}{69.9g} \times 100\% = 32.6 \%

5 0
3 years ago
Read 2 more answers
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