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Agata [3.3K]
2 years ago
15

ANSWER QUICK

Engineering
1 answer:
luda_lava [24]2 years ago
5 0

Answer:

u will need good car parts and a very well made engine

Explanation:

u need a good engine because if u only work on the outer layer of the car the inner parts will be slow and old and the car will have problems

You might be interested in
A tool chest has 650 N weight that acts through the midpoint of the chest. The chest is supported by feet at A and rollers at B.
erica [24]

Answer:

the value of horizontal force P is 170.625 N

the value of horizontal force at P = 227.5 N is that the block moves to right and this motion is due to sliding.

Explanation:

The first diagram attached below shows the free body diagram of the tool chest when it is sliding.

Let start out by calculating the friction force

F_f= \mu N_2

where :

F_f = friction force

\mu = coefficient of friction

N_2 = normal friction

Given that:

\mu = 0.3

F_f = 0.3 N_2

Using the equation of equilibrium along horizontal direction.

\sum f_x = 0

P - F_f = 0

P = 0.3 N_2   ----- Equation (1)

To determine the moment about point B ; we have the expression

\sum M_B  = 0

0 = N_2*70-W*35-P*100

where;

P = horizontal force

N_2 = normal force at support A

W = self- weight of tool chest

Replacing W = 650 N

0 = N_2*70-650*35-100*P

P = \frac{70 N_2-22750}{100} ----- equation (2)

Replacing  \frac{70 N_2-22750}{100}  for P in equation (1)

\frac{70N_2 -22750}{100} =0.3 N_2

N_2 = \frac{22750}{40}N_2 = 568.75 \ N

Plugging the value of N_2 = 568.75 \ N in equation (2)

P = \frac{70(568.75)-22750}{100} \\ \\ P = \frac{39812.5-22750}{100}  \\ \\ P = \frac{17062.5}{100}

P =170.625 N

Thus; the value of horizontal force P is 170.625 N

b)  From the second diagram attached the free body diagram; the free body diagram of the tool chest when it is tipping about point A is also shown below:

Taking the moments about point A:

\sum M_A = 0

-(P × 100)+ (W×35) = 0

P = \frac{W*35}{100}

Replacing 650 N  for W

P = \frac{650*35}{100}

P = 227.5 N

Thus; the value of horizontal force P, when the tool chest tipping about point A is 227.5 N

We conclude that the motion will be impending for the lowest value when P = 170.625 N and when P= 227.5 N

However; the value of horizontal force at P = 227.5 N is that the block moves to right and this motion is due to sliding.

5 0
3 years ago
As a global society with many political demarcations, what is the best way to preserve resources that are held in common? What s
MariettaO [177]

Answer:

kindly check the explanation section.

Explanation:

In order to be able to preserve resources that are common there is need for each countries in the world to agree and cooperate. Also, policies should be set and made the standard for all countries involved. The developed countries should come together with developing measures to make sure that there is mutual agreements between these countries to preserve common resources. For instance, the most common resource is the Ozone layer, the industrialization in developed countries causes the depletion of ozone.

The main problem that the kind of preservation entails is how to get money for countries that are not rich enough to follow the agreed laydown rules. Other problems are: differences in economies and each countries have their own ways of regulating and preserving resources.

8 0
2 years ago
Use the Hurricanes data and via Multiple regression select the three input variables: Min-pressure, Gender, Category in order to
S_A_V [24]

Answer:

Answer for the question:

Use the Hurricanes data and via Multiple regression select the three input variables: Min-pressure, Gender, Category in order to predict the All-Deaths. Pick one of the three variables that has the best P-value and re-do the regression using ONLY this one variable to predict the All-deaths. Answer the questions. (Numerical answers are rounded so choose the answer that matches the best).

is explained in the attachment.

Explanation:

Download pdf
6 0
3 years ago
An article that discusses pharaohs and gives examples and explains how they look. Which text structure is that?
fgiga [73]

The correct answer to this open question is the following.

The text structure of an article that discusses pharaohs and gives examples and explains how they look is a description.

The text structure called description allows the reader to fully know the characteristics of the people it is referring to, including some important details. That is why the author of a description text adds words like "such as" and "for example."

When describing something, the write is giving structure to the text and sequence. What comes first., what is followed, and so on.

That is why The text structure of an article that discusses pharaohs and gives examples and explains how they look is a description. It includes cause and effect sentences, and some comparisons in order to contrast an idea.

3 0
3 years ago
(a) The reverse-saturation current of a pn junction diode is IS = 10−11 A. Determine the diode voltage to produce currents of (i
kirill115 [55]

Answer:

The equation used to solve a diode is

i_d = I_se^\frac{V_d}{V_T}-1

  • i_d is the current going through the diode
  • I_s is your saturation current
  • V_D is the voltage across your diode
  • V_T is the voltage of the diode at a certain room temperature. by default, you always use V_T=25.9mV for room temperature.

If you look at the equation, i_d = I_se^\frac{V_d}{V_T}-1, you'd notice that the e^\frac{V_d}{V_T} grow exponentially fast, so we can ignore the -1 in the equation because it's so small compared to the exponential.

i_d = I_se^\frac{V_d}{V_T}-1

i_d\approx I_se^\frac{V_d}{V_T}

Therefore, use i_d= I_se^\frac{V_d}{V_T} to solve your equation.

Rearrange your equation to solve for V_D.

V_D=V_Tln(\frac{i_D}{I_s})

a.)

i.)

You're given I_s=10^{-11}A

at i_d=10\mu A,     V_D=V_Tln(\frac{i_D}{I_s})=(25.9\cdot10^{-3})ln(\frac{10\cdot10^{-6}}{10\cdot10^{-11}})=.298V

at i_d=100\mu A,   V_D=V_Tln(\frac{i_D}{I_s})=(25.9\cdot10^{-3})ln(\frac{100\cdot10^{-6}}{10\cdot10^{-11}})=.358V

at i_d=1mA,      V_D=V_Tln(\frac{i_D}{I_s})=(25.9\cdot10^{-3})ln(\frac{1\cdot10^{-3}}{10\cdot10^{-11}})=.417V

<em>note: always use</em>  V_T=25.9mV

ii.)

Just repeat part (i) but change to I_s=-5\cdot10^{-12}A

b.)

same process as part A. You do the rest of the problem by yourself.

4 0
3 years ago
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