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Pepsi [2]
3 years ago
6

HELP PLZ ANSWER ASAP!! 30 points!!

Chemistry
2 answers:
cricket20 [7]3 years ago
6 0

Answer:

Explanation:

5

eduard3 years ago
5 0
5.0 x 10 ^1 mL
Explanation:
M1V1 = M2V2
(0.25 M) (400 mL) = (2.0 M) V2
Divide both sides by 2.0 M
V2 = (0.25 M*400mL)/2.0 M
Molarity’s cancel out
V2 = 5.0 x 10^1 mL
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How much of a 0.250 M lithium hydroxide is required to neutralize 20.0 mL of 0.345M chlorous acid?
Bumek [7]

Answer:

27.6mL of LiOH 0.250M

Explanation:

The reaction of lithium hydroxide (LiOH) with chlorous acid (HClO₂) is:

LiOH + HClO₂ → LiClO₂ + H₂O

<em>That means, 1 mole of hydroxide reacts per mole of acid</em>

Moles of  20.0 mL = 0.0200L of 0.345M chlorous acid are:

0.0200L ₓ (0.345mol / L) = <em>6.90x10⁻³ moles of HClO₂</em>

To neutralize this acid, you need to add the same number of moles of LiOH, that is 6.90x10⁻³ moles. As the LiOH contains 0.250 moles / L:

6.90x10⁻³ moles ₓ (1L / 0.250mol) = 0.0276L of LiOH =

<h3>27.6mL of LiOH 0.250M</h3>
6 0
3 years ago
PLEASE HELP!!!! 20 MINS LEFT IM DYING PLS HELP
Zepler [3.9K]

Answer:

Kc = 0.20        

Explanation:

                  N₂O₄     ⇄    2NO₂

moles       5.3mol          2.3mol

Vol               5L                5L

Molarity    5.3/5M        2.3/5M

                = 1.06M     = 0.46M

Kc = [NO₂]²/[N₂O₄] =  (0.46)²/(1.06) = 0.1996 ≅ 0.20

6 0
3 years ago
Compare and contrast the uses of iron triad and the use of coinage metals
Arlecino [84]
<span>Answer: Iron triad are used in the process to create steel and other metal mixtures. Coinage Metals are used for much more than just coins, and many other elements besides these are made into coins.</span>
7 0
3 years ago
Read 2 more answers
How many atoms are in 0.650 mole of zinc?<br> NEED TO KNOW ASAP PLEASE
ryzh [129]
There are
4.517
⋅
10
23
atoms of Zn in 0.750 mols of Zn.
5 0
3 years ago
P 4 + 5O 2 P 4 O 10 , 1.5 moles of product was made in 30 seconds. What is the rate of reaction? 0.011 g/min 210 g/min 380 g/min
Airida [17]

Answer: 850.0 g/min.

Explanation:

  • The rate of the reaction = (ΔC/Δt) where,

ΔC is the change in concentration of reactants or products.

Δt is the change in time of the reaction proceeding.

  • The rate is needed to be calculated in (g/min).
  • We need to calculate the amount of the product in (g) via using the relation (n = mass / molar mass).
  • mass (g) = n x molar mass,
  • n = 1.5 moles and molar mass of P₄O₁₀ = 283.88 g/mol.
  • m = 1.5 x 283.88 = 425.82 g.
  • ΔC = 425.82 g and Δt = 30 s / 60 = 0.5 min.
  • The rate of the reaction = ΔC / Δt = (425.82 g / 0.5 min) = 851.64 g/min.

<em>can be approximated to 850.0 g/min.</em>

6 0
3 years ago
Read 2 more answers
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