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Arturiano [62]
4 years ago
7

Plzz need help will give alot of point!!!!!!

Chemistry
1 answer:
Alekssandra [29.7K]4 years ago
6 0

Answer:

4.68x10⁻⁵N

Explanation:

The pH is defined as -log [H⁺]. If an acid has a pH of 4.33, [H⁺] is:

pH = -log [H⁺]

4.33 =  -log [H⁺]

10^(-4.33) = [H⁺]

4.68x10⁻⁵M = [H⁺]

The [H⁺] is in molarity units, that is mole / L. Normality has as units equivalent / L. As the equivalent in an acid-base reaction is defined as the number of moles of H⁺, in this case:

4.68x10⁻⁵M = <em>4.68x10⁻⁵N</em>

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Answer:

El volumen del gas era 12.95 L

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Se relaciona la presión y el volumen mediante la ley de Boyle, que dice:

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La ley de Boyle se expresa matemáticamente como:  P*V=k

Por otro lado, la Ley de Charles consiste en la relación que existe entre el volumen y la temperatura absoluta de una cierta cantidad de gas ideal, el cual se mantiene a una presión constante. Esta ley dice que cuando la cantidad de gas y de presión se mantienen constantes, el cociente que existe entre el volumen y la temperatura siempre tendrán el mismo valor:  

\frac{V}{T}=k

Por último, la Ley de Gay Lussac dice que la temperatura absoluta y la presión son directamente proporcionales. Es decir, cuando se mantiene todo lo demás constante, mientras suba la temperatura de un gas subirá también su presión. Y mientras la temperatura del gas baje, lo mismo ocurrirá con la presión:

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\frac{P*V}{T} =k

Cuando se desean estudiar dos diferentes estados, uno inicial y una final de un gas, se puede aplicar:

\frac{P1*V1}{T1} =\frac{P2*V2}{T2}

Recordando que la temperatura debe usarse en grados Kelvin, conoces los siguientes datos:

  • P1: 750 torr
  • V1: 8.5 L
  • T1: 20°C= 293°K (siendo 0°C=273°K)
  • P2: 425 torr
  • V2: ?
  • T2: -20°C= 253 °K

Reemplazando:

\frac{750 torr*8.5 L}{293K} =\frac{425 torr*V2}{253 K}

Resolviendo:

V2=\frac{750 torr*8.5 L}{293K} *\frac{253 K}{425 torr}

V2= 12.95 L

<u><em>El volumen del gas era 12.95 L</em></u>

<u><em></em></u>

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