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Arturiano [62]
3 years ago
7

Plzz need help will give alot of point!!!!!!

Chemistry
1 answer:
Alekssandra [29.7K]3 years ago
6 0

Answer:

4.68x10⁻⁵N

Explanation:

The pH is defined as -log [H⁺]. If an acid has a pH of 4.33, [H⁺] is:

pH = -log [H⁺]

4.33 =  -log [H⁺]

10^(-4.33) = [H⁺]

4.68x10⁻⁵M = [H⁺]

The [H⁺] is in molarity units, that is mole / L. Normality has as units equivalent / L. As the equivalent in an acid-base reaction is defined as the number of moles of H⁺, in this case:

4.68x10⁻⁵M = <em>4.68x10⁻⁵N</em>

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Compare a mixture and a compound. How are they alike?
LenKa [72]

Answer:

gnzl8303

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Explanation:

8 0
3 years ago
A 250 mL sample of gas is collected over water at 35°C and at a total pressure of 735 mm Hg. If the vapor pressure of water at 3
ELEN [110]

Answer:

The volume of the gas sample at standard pressure is <u>819.5ml</u>

Explanation:

Solution Given:

let volume be V and temperature be T and pressure be P.

V_1=250ml

V_2=?

P_{total}=735 mmhg

1 torr= 1 mmhg

42.2 torr=42.2 mmhg

so,

P_{water}=42.2mmhg

T_1=35°C=35+273=308 K

Now

firstly we need to find the pressure due to gas along by subtracting the vapor pressure of water.

P_{gas}=P_{total}-P_{water}

=735-42.2=692.8 mmhg

Now

By using combined gas law equation:

\frac{P_1*V_1}{T_1} =\frac{P_2*V_2}{T_2}

V_2=\frac{P_1*}{P_2}*\frac{T_2}{T_1} *V_1

V_2=\frac{P_gas}{P_2}*\frac{T_2}{T_1} *V_1

Here P_2 \:and\: T_2 are standard pressure and temperature respectively.

we have

P_2=750mmhg \:and\: T_2=273K

Substituting value, we get

V_2=\frac{692.8}{750}*\frac{273}{308} *250

V_2= 819.51 ml

4 0
1 year ago
In a solution, when the suspension of one kind of molecules is blended or dissolved with another, the ________ properties are no
Sidana [21]

Answer:

chemical

Explanation:

The chemical properties determine the identity of a substance and are not changed when there is no reaction. In the solution, what takes place is a physical change, which is a change of state (for example, going from solid to aqueous form).

8 0
3 years ago
How do you solve this problem
ad-work [718]

Answer: Volume of gas in the stomach, V = 0.0318L or 31.8mL

Explanation:

The number of moles of oxygen will remain constant even though the liquid oxygen will undergo a change of state to gaseous inside the person's stomach due to an increase in temperature.

<em>Number of moles of oxygen gas = mass/molar mass</em>

molar mass of oxygen gas = 32 g/mol

mass of oxygen gas = density * volume

mass of oxygen gas = 1.149 g/ml * 0.035 ml

mass of oxygen gas = 0.040215 g

Number of moles of oxygen gas = 0.0402 g/(32 g/mol)

Number of moles of oxygen gas = 0.00125 moles

<em>Using the ideal gas equation, PV=nRT</em>

where P = 1.0 atm, V = ?, n = 0.00125 moles, R = 0.082 L*atm/K*mol, T = (37 + 273)K = 310 K

<em>V = nRT/P</em>

V = (0.00125moles) * (0.082 L*atm/K*mol) * (310 K) / 1 atm

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3 0
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A reaction that absorbs energy
coldgirl [10]

Answer:

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Explanation:

5 0
3 years ago
Read 2 more answers
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