Explanation:
At first sight, it doesn’t make sense that both fission and fusion release energy.
The key is in how tightly the nucleons are held together in a nucleus. If a nuclear reaction produces nuclei that are more tightly bound than the originals, then the excess energy will be released.
It turns out that the most tightly bound atomic nuclei are around the size of iron-56.
Thus, if you split a nucleus that is much larger than iron into smaller fragments, you will release energy because the smaller fragments are at a lower energy than the original nucleus.
If instead you fuse very light nuclei to get bigger products, energy is again released because the nucleons in the products are more tightly bound than in the original nuclei.
https://socratic.org/questions/how-are-fusion-and-fission-similar
Answer:
Explanation:
The total energy of the satellite when it is still in orbit is given by the formula
where
G is the gravitational constant
m = 525 kg is the mass of the satellite
is the Earth's mass
r is the distance of the satellite from the Earth's center, so it is the sum of the Earth's radius and the altitude of the satellite:
So the initial total energy is
When the satellite hits the ground, it is now on Earth's surface, so
so its gravitational potential energy is
And since it hits the ground with speed
it also has kinetic energy:
So the total energy when the satellite hits the ground is
So the energy transformed into internal energy due to air friction is the difference between the total initial energy and the total final energy of the satellite:
Answer:
68kg
Explanation:
1 cm^3 is the same as 1 mL and there are 5000mL in 5L
Therefore if the density is 13.6g/mL we multiply 13.6 by 5000 to get the amount of grams required = 68000g which is 68kg
Answer:
21.59 m/s
Explanation:
recall that one of the equations of motions can be expressed as
v² = u² + 2as
where,
v = final velocity (we are asked to find this)
u = initial velocity = 0m/s (because it says that it starts from rest)
a = acceleration = 3.7m/s²
s = distance travelled = 63 m
simply substitute the known values above into the equation:
v² = u² + 2as
v² = 0² + 2(3.7)(63)
v² = 466.2
v = √466.2
v = 21.59 m/s
Answer:
Explanation:
Since this is a distance v time graph, the slope of the line from 1s to 3s is the velocity. However, it looks like, at t=3, the velocity is 0, so getting the definite velocity is not going to happen. We can estimate it as closely as possible. Since the line is tending from the upper left to the lower right, the slope is negative, so the velocity is also negative. That leaves only C or D as our answers. And the slope is closer to -1 than to -5, so choice D. is the one you want.
