Answer:
9
Explanation:
You get this answer by adding the protons and neutrons together.
Answer:
<h2>
a) Q = 0.759µC</h2><h2>
b) E = 39.5µJ</h2>
Explanation:
a) The charge Q on the positive charge capacitor can be gotten using the formula Q = CV
C = capacitance of the capacitor (in Farads )
V = voltage (in volts) = 100V
C = ∈A/d
∈ = permittivity of free space = 8.85 × 10^-12 F/m
A = cross sectional area = 600 cm²
d= distance between the plates = 0.7cm
C = 8.85 × 10^-12 * 600/0.7
C = 7.59*10^-9Farads
Q = 7.59*10^-9 * 100
Q = 7.59*10^-7Coulombs
Q = 0.759*10^-6C
Q = 0.759µC
b) Energy stored in a capacitor is expressed as E = 1/2CV²
E = 1/2 * 7.59*10^-9 * 100²
E = 0.0000395Joules
E = 39.5*10^-6Joules
E = 39.5µJ
Answer:
In parallel circuits, if one element has a problem, it can be eliminated and the rest of the elements continue to work.
Explanation:
There are two ways to connect electrical circuits, in series and in parallel.
Series circuits have the problem that when one element is damaged, the entire circuit is interrupted and runs out of power.
In parallel circuits, if one element has a problem, it can be eliminated and the rest of the elements continue to work.
In Breaker it is connected in series so that when some maintenance is needed, all the energy can be interrupted simultaneously and if some equipment tries to consume a lot of energy, the circuit prevents this action by interrupting the energy of the entire circuit
Answer:
(h₁-h₂) = 2.30 10² m
Explanation:
The pressure depends on the height with the formula
P = P_atm + rho g h
Let's apply this expression for the building
P₁ = P_atm + rho_air g h₁
P₂ = P_atm + rho_air g h₂
Subtract
P₁ - P₂ = roh_air g (h₁ –h₂)
The measured pressure is in mm Hg to take this unit to units of pressure must be multiplied by the density of mercury and the acceleration of gravity
P₁- P₂ = rho_Hg g (h₁-h₂) _Hg
rho_Hg g (h₁-h₂) _Hg = roh_air g (h₁ –h₂)
(h₁ –h₂) = rho_Hg / rho_air (h₁-h₂) _ Hg
Let's calculate
(h₁-h₂) = 13600 / 1.18 (695-675)
(h₁-h₂) = 2.30 10⁵ mm
Let's reduce to meter
(h₁-h₂) = 2.30 10⁵ mm (1 m / 10³ mm)
(h₁-h₂) = 2.30 10² m
Answer:
a = 3.33 m/s²
Explanation:
The horizontal acceleration of the dog can be found by using Newton's Second Law of Motion as follows:
F = ma
where,
F = Unbalanced force applied on the dog = 11 N - 10 N = 1 N
m = mass of the dog = 0.3 kg
a = horizontal acceleration of dog = ?
Therefore,
1 N = 0.3 kg(a)
a = 1 N/0.3 kg
<u>a = 3.33 m/s²</u>
