The combined momentum is 4000 kg m/s south
Explanation:
The total combined momentum of the two cars is given by the vector addition of the momenta of the two cars.
For this problem, we choose north as positive direction and south as negative direction.
The momentum of the first car travelling north is given by:

where
is the mass of the car
is its velocity
Substituting,

The momentum of the second car travelling south is given by:

where
is the mass of the car
is its velocity (negative because the car travels south)
Substituting,

And therefore, the combined momentum is

where the negative sign means the direction of the total momentum is south.
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Answer:
y=8
Explanation:
every time you multiply x by 3 you divide y by 3.
x=2, multiply it by 3: x=6
y=24, divide it by 3: y=8
solution:
y = v0t + ½at²
1150 = 79t + ½3.9t²
0 = 3.9t² + 158t - 2300
from quadratic equations and eliminating the negative answer
t = (-158 + v158² -4(3.9)(-2300)) / 2(3.9)
t = 11.37 s to engine cut-off
the velocity at that time is
v = v0 + at
v = 79 + 3.9(11.37)
v = 123.3 m/s
it rises for an additional time
v = gt
t = v/g
t = 123.3 / 9.8
t = 12.59 s
gaining more altitude
y = ½vt
y = 123.3(12.59) /2
y = 776 m
for a peak height of
y = 776 + 1150
Answer:

Explanation:
from snells law we have following relation
is refractive index of air
n' - refractive index of air below
i is angle of incidence = 90 - 1.30 = 88.70^o
r is refraction angle
plugging all value in above formula

