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Debora [2.8K]
3 years ago
6

What mass of Neon gas is needed to occupy 2.56 L tube at STP?

Chemistry
1 answer:
malfutka [58]3 years ago
6 0

Answer:

Mass = 2.222 g

Explanation:

Given data:

Volume of  neon gas = 2.56 L

Temperature = 273 K

Pressure = 1 atm

Mass of neon gas = ?

Solution:

PV = nRT

n = PV / RT

n = 1 atm × 2.56 L/ 0.0821 atm. L / mol. K× 273 K

n = 2.56 L.atm / 22.4 atm. L/ mol

n = 0.11 mol

Mass = number of moles × molar mass

Mass = 0.11 mol × 20.2 g/mol

Mass = 2.222 g

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If you have 100 ml of a 0.10 m tris buffer (pka 8.3) at ph 8.3 and you add 3.0 ml of 1.0 m hcl, what will be the new ph?
sukhopar [10]

The new pH is 7.69.

According to Hendersen Hasselbach equation;

The Henderson Hasselbalch equation is an approximate equation that shows the relationship between the pH or pOH of a solution and the pKa or pKb and the ratio of the concentrations of the dissociated chemical species. To calculate the pH of the buffer solution made by mixing salt and weak acid/base. It is used to calculate the pKa value. Prepare buffer solution of needed pH.

                       pH = pKa + log10 ([A–]/[HA])

Here, 100 mL  of  0.10 m TRIS buffer pH 8.3

                 pka = 8.3

         0.005 mol of TRIS.

∴  8.3 = 8.3 + log \frac{[0.005]}{[0.005]}

<em>    </em>inverse log 0 = \frac{[B]}{[A]}

   \frac{[B]}{[A]} = 1

Given; 3.0 ml of 1.0 m hcl.

           pka = 8.3

           0.003 mol of HCL.

pH = 8.3 + log \frac{[0.005-0.003]}{[0.005+0.003]}\\pH = 8.3 + log \frac{[0.002]}{[0.008]}\\\\pH = 8.3 + log {0.25}\\\\pH = 8.3 + (-0.62)\\pH = 7.69

Therefore, the new pH is 7.69.

Learn more about pH here:

brainly.com/question/24595796

#SPJ1

 

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2 years ago
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I believe it means idea because a Web is out line to a a more structured idea
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3 years ago
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It’s 2.0 molecules.

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