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Debora [2.8K]
3 years ago
6

What mass of Neon gas is needed to occupy 2.56 L tube at STP?

Chemistry
1 answer:
malfutka [58]3 years ago
6 0

Answer:

Mass = 2.222 g

Explanation:

Given data:

Volume of  neon gas = 2.56 L

Temperature = 273 K

Pressure = 1 atm

Mass of neon gas = ?

Solution:

PV = nRT

n = PV / RT

n = 1 atm × 2.56 L/ 0.0821 atm. L / mol. K× 273 K

n = 2.56 L.atm / 22.4 atm. L/ mol

n = 0.11 mol

Mass = number of moles × molar mass

Mass = 0.11 mol × 20.2 g/mol

Mass = 2.222 g

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Calculate the pH of a buffer solution prepared by mixing 75.0 mL of 1.00 M lactic acid and 25.0 mL of 0.50 M sodium lactate.
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From the calculations, the pH of the buffer is 3.1.

<h3>What is the pH of the buffer solution?</h3>

The  Henderson-Hasselbach equation comes in handy when we deal with the pH of a buffer solution. From that equation;

pH = pKa + log[(salt/acid]

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Total volume = ( 25 + 75)/1000 = 0.1 L

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6 0
2 years ago
What is the preasure in atmospheres of 20 mol of nitrogen gas in 36.2 L cylinder at 25 degrees C?
Savatey [412]

Answer:

P = 13.5 atm

Explanation:

Given that

No. of moles, n = 20 moles

Volume of nitrogen gas = 36.2 L

Temperature = 25°C = 298 K

We need to find the pressure of the gas. Using the ideal gas equation

PV = nRT

Where

R is gas constant, R=0.082057\ L-atm/K-mol

So,

P=\dfrac{nRT}{V}\\\\P=\dfrac{20\times 0.082057\times 298}{36.2 }\\\\P=13.5\ atm

so, the pressure of the gas is equal to 13.5 atm.

7 0
3 years ago
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