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NeX [460]
3 years ago
8

What volume of hydrogen iodide is produced when 118 liters of hydrogen gas react according to the following reaction? (All gases

are at the same temperature and pressure.) hydrogen(g) + iodine(s) hydrogen iodide(g) liters hydrogen iodide
Chemistry
1 answer:
Nadya [2.5K]3 years ago
4 0

Answer:

V_{HI}=236LHI

Explanation:

Hello,

In this case, for the given balanced chemical reaction:

H_2(g)+I_2(g)\rightarrow 2HI(g)

Thus, since hydrogen and hydrogen iodide are in a 1:2 mole ratio, we can easily compute the yielded volume as shown below:

V_{HI}=118LH_2*\frac{2molHI}{1molH_2} \\\\V_{HI}=236LHI

Thus, is possible, due to the Avogadro's law which allows to relate moles and volume by a directly proportional relationship.

Regards.

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6 0
3 years ago
What is the volume of 3.00 M sulfuric aid that contain 9.809 g of H2SO4 (98.09g/mol)
Slav-nsk [51]

Given :

Molarity of sulfuric acid solution is 3.0 M.

Amount of sulfuric acid present in solution is 9.809 g.

To Find :

The volume of solution.

Solution :

We know, molarity is given by :

Molarity = \dfrac{number \ of \ moles \times 1000}{Volume\ ( ml )}\\\\M = \dfrac{w \times 1000}{M.M \times V}\\\\3 = \dfrac{9.809\times 1000}{98.09 \times V}\\\\V = \dfrac{1000}{10\times 3}\  ml\\\\V = 33.33 \ ml

Therefore, volume required is 33.33 ml .

5 0
3 years ago
If 5.3 g of gallium reactions with 5.3 g of oxygen according to the following reaction, how many grams of gallium oxide can be p
monitta

Answer:

can you help mine please

How many molecules of chlorine are needed to react with 56.Og of iron to form Iron (III) chloride (FeCl3)?

5 0
2 years ago
**ASAP**
jek_recluse [69]

the answer is C) . I hope this was helpful!

4 0
3 years ago
Read 2 more answers
A chemist has 3.55x1022 molecules of nitrogen monoxide. How
Alina [70]

Answer:

<h2>0.059 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.55 \times  {10}^{22} }{6.02 \times  {10}^{23} }  \\  = 0.05897...

We have the final answer as

<h3>0.059 moles</h3>

Hope this helps you

6 0
3 years ago
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