What volume of hydrogen iodide is produced when 118 liters of hydrogen gas react according to the following reaction? (All gases
1 answer:
Answer:
Explanation:
Hello,
In this case, for the given balanced chemical reaction:
Thus, since hydrogen and hydrogen iodide are in a 1:2 mole ratio, we can easily compute the yielded volume as shown below:
Thus, is possible, due to the Avogadro's law which allows to relate moles and volume by a directly proportional relationship.
Regards.
You might be interested in
Answer:
Explanation:
This is a typical double replacement or double decomposition reaction. In this kind of reaction, it involves the combination of ionic compounds which exchange their partners to form new compounds. Typical of these reaction is the formation of precipitates which are insoluble compounds.
The reaction equation is shown below:
AgNO₃ + K₂SO₄
→ 2KNO₃
+ AgSO₄
)
From the rule of solubility:
- All trioxonitrate(v) salts are soluble
- Salts of silver sulfates are slightly soluble. This will form the precipitate in the solution.
We can write the ionic equation as:
Ag⁺ + NO₃⁻
+ 2K⁺
+ SO₄²⁻
→ AgSO₄
+ 2K⁺ + NO₃⁻
The spectator ions or non-reactive ions are those ions that appears on both sides of the equation. These ions are the potassium and trioxonitrate ions. We cancel them out to give the net ionic equation of the reaction:
Ag⁺ + SO₄²⁻
→ AgSO₄