Question

What volume of hydrogen iodide is produced when 118 liters of hydrogen gas react according to the following reaction? (All gases are at the same temperature and pressure.) hydrogen(g) + iodine(s) hydrogen iodide(g) liters hydrogen iodide

Answer 1

Answer:

$V_{HI}=236LHI$

Explanation:

Hello,

In this case, for the given balanced chemical reaction:

$H_2(g)+I_2(g)\rightarrow 2HI(g)$

Thus, since hydrogen and hydrogen iodide are in a 1:2 mole ratio, we can easily compute the yielded volume as shown below:

$V_{HI}=118LH_2*\frac{2molHI}{1molH_2} \\\\V_{HI}=236LHI$

Thus, is possible, due to the Avogadro's law which allows to relate moles and volume by a directly proportional relationship.

Regards.