Answer:

Explanation:
<em>Ferrous Sulphate</em>
<em> is generally found as Lime-Green Crystals. On heating, these crystals almost immediately turn white-yellow. They then, break down to produce an anhydrous mixture of Sulphur Trioxide </em>
<em>, Sulphur Dioxide </em>
<em> as well as Ferric Oxide </em>
<em>.</em>
<em>We can hence, frame a skeletal equation of this reaction and try to balance it.</em>
<em>Hence,</em>

<em>Now,</em>
<em>a)In order to balance it through the 'Hit &Trial Method', we'll follow a series of </em><em>steps</em><em>:</em>
<em>1. First, lets compare the number of Fe (Iron) atoms on the RHS and LHS. We find that, the no. of Fe Atoms on the RHS is twice the number of Fe Atoms on the LHS. We hence, add a co-effecient 2 beside </em>
.
<em>2. Now, Iron atoms, Sulphur Atoms and Oxygen atoms occur 2, 2, 8 respectively on both the sides:</em>
<em> Hence, As all the other elements as well as iron, balance, we've arrived upon our Balanced Equation :</em>
<em> </em>
<em>b) We know that, decomposition reactions are [generally] endothermic reactions in which Large Compounds </em><em>decompose </em><em>into smaller elements and compounds. Here, as Ferrous Sulphate </em><em>decomposes </em><em>into Sulphur Dioxide, Sulphur Trioxide and Ferric Oxide, the reaction that occurs here is </em><em>Decomposition Reaction.</em>
Mg gained mass because it went from being a single element (on the reactant side) to being a molecule (on the product side).
This question is incomplete, the complete question is;
The rate constant for the reaction 3A equals 4B is 6.00 × 10⁻³ L.mol⁻¹min⁻¹.
how long will it take the concentration of A to drop from 0.75 to 0.25M ?
from the unit of the rate constant we know it is a second reaction order
OPTIONS
a) 2.2×10^−3 min
b) 5.5×10^−3 min
c) 180 min
d) 440 min
e) 5.0×10^2 min
Answer:
it will take 440 min for the concentration of A to drop from 0.75 to 0.25M
Option d) 440 min is the correct answer
Explanation:
Given that;
Rate constant K = 6.00 × 10⁻³ L.mol⁻¹min⁻¹
3A → 4B
given that it is a second reaction order;
k = 1/t [ 1/A - 1/A₀]
kt = [ 1/A - 1/A₀]
t = [ 1/A - 1/A₀] / k
K is the rate constant(6.00 × 10⁻³)
A₀ is initial concentration( 0.75 )
A is final concentration(0.25)
t is time required = ?
so we substitute our values into the equation
t = [ (1/0.25) - (1/0.75)] / (6.00 × 10⁻³)
t = 2.6666 / (6.00 × 10⁻³)
t = 444.34 ≈ 440 min {significant figures}
Therefore it will take 440 min for the concentration of A to drop from 0.75 to 0.25M
Option d) 440 min is the correct answer
Answer: The pressure of the He is 2.97 atm
Explanation:
According to Dalton's law, the total pressure is the sum of individual pressures.
Given :
=total pressure of gases = 6.50 atm
= partial pressure of Nitrogen = 1.23 atm
= partial pressure of oxygen = 2.3 atm
= partial pressure of Helium = ?
putting in the values we get:
The pressure of the He is 2.97 atm