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masya89 [10]
2 years ago
11

What is the application of the emission spectra regarding elements?

Chemistry
1 answer:
malfutka [58]2 years ago
8 0

The emission spectrum of a chemical element or chemical compound is the spectrum of frequencies of electromagnetic radiation emitted due to an atom or molecule making a transition from a high energy state to a lower energy state. The photon energy of the emitted photon is equal to the energy difference between the two states. There are many possible electron transitions for each atom, and each transition has a specific energy difference. This collection of different transitions, leading to different radiated wavelengths, make up an emission spectrum. Each element's emission spectrum is unique. Therefore, spectroscopy can be used to identify elements in matter of unknown composition. Similarly, the emission spectra of molecules can be used in chemical analysis of substances.

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In which of the following is the number of neutrons correctly represented? A. fluorine: atomic number 9, mass 19, neutrons 0 B.
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4 0
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Which describes an object in projectile motion?
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When 1 mol each of C2H5OH and CH3CO2H are allowed to react in 1 L of the solvent dioxane, equilibrium is established when 13 mol
taurus [48]

Answer:

  • Keq = 4

Explanation:

The correct statement is:

When 1 mol each of C₂H₅OH and CH₃CO₂H are allowed to react in 1 L of the solvent dioxane, equilibrium is established when 1/3 mol of each of the reactants remains. Calculate the equilibrium constant for the reaction. (Note: Water is a solute in this reaction.)

<u>1. Equilibrium equation</u>

  • C₂H₅OH + CH₃CO₂H     ⇄    CH₃CO₂C₂H₅ +   H₂O

               ↑                  ↑                          ↑                    ↑

          ethanol     acetic acid        ethyl acetate       water

<u>2. Equilibrium constant</u>

  • Keq = [Products] / [Reactants], each raised to tis stoichiometrical coefficient.

Since water is also a solute in this reaction (the solvent is dioxane) its concentration will appear in the equilibrium constant.

  • Keq=\frac{[CH_3CO_2C_2H_5]\cdot [H_2O]}{[C_2H_5OH]\cdot [CH_3CO_2H]}

<u>3. Equlibrium concentrations:</u>

Moles

                  C₂H₅OH + CH₃CO₂H     ⇄    CH₃CO₂C₂H₅ +   H₂O

Initial                1                  1                                 0                  0

Change          -2/3            -2/3                            +2/3             +2/3

End                  1/3               1/3                              2/3              2/3

Since the volume is 1 liter, the concentration is equal to the number of moles

<u>4. Calculations:</u>

Keq=\frac{[CH_3CO_2C_2H_5]\cdot [H_2O]}{[C_2H_5OH]\cdot [CH_3CO_2H]}=\frac{2/3\cdot 2/3}{1/3\cdot 1/3}=4

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3 years ago
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