Answer:
The only solution can be (0,-3) point.
Step-by-step explanation:
We have to judge whether the points in options are the solution to the graphed inequality or not.
The first point is (5,-5) which not included in the shaded region of the graph. Hence, it can not be a solution.
The second point is (6,0) which not included in the shaded region of the graph. Hence, it can not be a solution.
The third point is (0,-5) which not included in the shaded region of the graph. Hence, it can not be a solution.
The fourth point is (0,-3). It is on the firm red line which is included in the shaded region of the graph. Hence, it is a solution.
Therefore, the only solution can be (0,-3) point. (Answer)
Answer:
3/2
Step-by-step explanation:
3/4 * 2 = 6/4 = 3/2
P= a+b+c = 76
side a = 2b = 30
side b = b = 15
side c = 2b + 1 = 31
Answer:
b
Step-by-step explanation:
vertical line through x at one
vertical lines have undefined slopes
can take two points to verify (1,1) (1,2) m=<u> 2-1</u>
1-1
<u> 1 </u>
0 undefined zero in denominator
To factor out you have to think what multiples to AC and adds to B.
Ax^2+Bx+C
So... for this problem AxC=1x-24 or -24
B is -2.
So what two numbers multiply to -24: -3x8, -8x3, -4x6, -6x4, -2x12, -12x2.
Out of these, which adds to -2: -6+4=-2.
So the factors are (d-6)(d+4)
OR the longer way, which you really only use if A is not equal to 1.
Use the terms above and then rewrite the equation with two middle terms: d^2+4d-6d-24
Group the terms by using addition: (d^2+4d)+(6d-24)
Find what they have in common and factor it out. For the first, it's d. They both have d. So: d(d+4)
To check this, distribute the d. It should equal the first set lf parenthesis.
For the second, they have a number in common. 6 is a multiple of 24 so you can take that out: -6(d+4)
If the terms inside the parenthesis are the same, that's good. It means we can pair the insides and the outsides together to form the factors.
The two terms outside the parenthesis: d, -6 group together and become (d-6)
The inside terms stay the same: (d+4)
(d-6)(d+4)
Again, this is the longer way and no necessary for a problem like this. But if it was 2d^2, then this would be perfecf.
