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3 years ago

Which statement is true about an empirical formula?

2 answers:

6 0

The statement that is true about an empirical formula is it is the simplest ratio of atoms in a formula unit. The answer is number 2. The rest of the statements do not answer the question above.

motikmotik3 years ago

3 0

Answer:

2. It is the simplest ratio of atoms in a formula unit.

Explanation:

The empirical formula refers to how to provide the minimum proportion in which chemical elements combine into one substance. Sometimes it may happen that the minimum formula is equal to the molecular formula of the compound; However, this is not always true. In short, the empirical formula refers to the simplest ratio of atoms in a unit of formula.

For example, the empirical or minimal formula of water is H2O, indicating that there is a 2: 1 ratio between the elements that make up water molecules. And, coincidentally, this is also the molecular formula of water.

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The mass of a length of metal wire is 45 g. When the wire is placed in a graduated

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5 ml=5 cm³ , density=mass/volume=45/5= 9 g/cm³ therefore answer B

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4 years ago

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Calcium phosphate reacts with hydrochloride acid to produce calcium chloride and phosphoric acid. This is the balanced chemical

Mashcka [7]

Answer: 0.664 moles and 65.1 grams EDMENTUM USERS

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3 years ago

A ground test utilizing an auxiliary current electrode and an auxiliary potential electrode is known as the______.

kompoz [17]

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Explanation:

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2 years ago

The mechanical advantage of a door knob that allows you to move a boli

taurus [48]

Answer:

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4 years ago

What is a possible quantum number set for an electron in the 3s orbital of a magnesium atom

Alik [6]

n = 3
l = 0
$m_l$ = 0

$m_s$ = 1/2 or -1/2

<h3>Explanation</h3>

There are four quantum numbers in an electron that orbits the atom.

n, the principal quantum number.
l, the angular quantum number.
$m_l$ , the magnetic quantum number.
$m_s$ , the spin quantum number.

n is a positive integer. The value of n indicates the main shell of the electron. The electron in question is in the 3s orbital. As a result, n = 3.

l is a non-negative integer. The value of l indicates the type of subshell ("orbital") of the electron. The types of subshells possible depends on the main shell. For example, both s and p orbitals exist in the second main shell. However, only the s orbital exists in the first main shell. The value of l ranges from 0 to n - 1.

l = 0 indicates an s orbital.
l = 1 indicates a p orbital.
l = 2 indicates a d orbital.
l = 3 indicates an f orbital.

The electron in question is in an s orbital. As a result, l = 0.

$m_l$ is an integer. The value of $m_l$ indicates the position of the electron within the subshell. The range of $m_l$ depends on the value of l. $m_l$ ranges from -l to l (that's -l, ..., -1, 0, 1, ... l). Accordingly, there are 2 l + 1 orbitals in a l subshell. l = 0 for this 3s electron. There's only one orbital in the 3s subshell. The only $m_l$ value possible for this electron is 0.

The value of $m_s$ is either - 1/2 or 1/2. It indicates the position of an electron within a single orbital. The value of $m_s$ does not depend on that of n, l, or $m_l$ . However, by the Pauli Exclusion Principle, at least one of the four numbers must differ for two electrons in the same atom. In case all three of n, l, and $m_l$ are the same, the two electrons must differ in $m_s$ . However, this question asks only for the number of one single electron. Thus, giving either - 1/2 or 1/2 shall work.

<h3>Reference</h3>

Vitz et. al, "5.8 Quantum Numbers (Electronic)", ChemPRIME (Moore et al.), Chemistry Libretexts. 27 Oct 2017.

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4 years ago