Answer:
a) 42 m/s, positive direction (to the east), b) 42 m/s, negative direction (to the west).
Explanation:
a) Let consider that Car A is moving at positive direction. Then, the relative velocity of Car A as seen by the driver of Car B is:
42 m/s, positive direction (to the east).
b) The relative velocity of Car B as seen by the drive of Car A is:
42 m/s, negative direction (to the west).
Answer:
A because the bigger it is the the more force needs to act apond it
Explanation:
This is an interesting (read tricky!) variation of Rydberg Eqn calculation.
Rydberg Eqn: 1/λ = R [1/n1^2 - 1/n2^2]
Where λ is the wavelength of the light; 1282.17 nm = 1282.17×10^-9 m
R is the Rydberg constant: R = 1.09737×10^7 m-1
n2 = 5 (emission)
Hence 1/(1282.17 ×10^-9) = 1.09737× 10^7 [1/n1^2 – 1/25^2]
Some rearranging and collecting up terms:
1 = (1282.17 ×10^-9) (1.09737× 10^7)[1/n2 -1/25]
1= 14.07[1/n^2 – 1/25]
1 =14.07/n^2 – (14.07/25)
14.07n^2 = 1 + 0.5628
n = √(14.07/1.5628) = 3
"Acceleration" means any change in the speed or direction of motion ... speeding up, slowing down, or turning. So . . .
<span>-- </span><span>The distance traveled in a certain time may increase or decrease.
-- The displacement covered in a certain time may increase or decrease.
-- The speed of the object may increase or decrease.
-- The velocity of the object (speed/direction) will change.
</span>
Hope this helps..
When a car is slowing down, it has a negative acceleration. Although it is not going a negative speed, it is decreasing in velocity, which is the definition of a negative acceleration.
Hope this helps!
