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Nina [5.8K]
3 years ago
6

The motion of an object thrown at an angle is projectile motion. True or false

Physics
2 answers:
Nezavi [6.7K]3 years ago
6 0

Answer:

true. thank you!

Explanation:

Elan Coil [88]3 years ago
5 0

Answer:

True Mate ;)

Explanation:

Have a Good Day! ;)

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Light with a wavelength of 395 nm illuminates a metal cathode. The maximum kinetic energy of the emitted electrons is 0.76 eV .
lutik1710 [3]

Answer:

520.8 nm

Explanation:

We are given that

\lambda=395 nm=395\times 10^{-9} m

1 nm=10^{-9} m

Maximum kinetic energy,K_{max}=0.76 eV=0.76\times 1.6\times 10^{-19} V

1 e=1.6\times 10^{-19} C

We have to find the maximum wavelength of light.

We know that

h\nu=\frac{hc}{\lambda_0}+K_{max}

Where c=3\times 10^8 m/s

h=6.625\times 10^{-34}

6.625\times 10^{-34}\times \frac{3\times 10^8}{395\times 10^{-9}}=\frac{6.625\times 10^{-34}\times 3\times 10^8}{\lambda_0}+0.76\times 1.6\times10^{-19}

6.625\times 10^{-34}\times \frac{3\times 10^8}{395\times 10^{-9}}- 0.76\times 1.6\times10^{-19}=\frac{6.625\times 10^{-34}\times 3\times 10^8}{\lambda_0}

\lambda_0=\frac{6.625\times 10^{-34}\times 3\times 10^8}{6.625\times 10^{-34}\times \frac{3\times 10^8}{395\times 10^{-9}}- 0.76\times 1.6\times10^{-19}}

\lambda_0=5.208\times 10^{-7} m=520.8 nm

6 0
3 years ago
What is wind shear? When wind is moving extremely fast in one direction When wind is moving with a circular motion When two wind
AlexFokin [52]

Answer:

C) When wind direction or wind speed changes with altitude :)

Explanation:

7 0
3 years ago
The process in which acids and bases react so that the properties of both are lost to form water and a salt is called __________
makvit [3.9K]
The process is called neutralization.
Hope this helps!
4 0
3 years ago
Please help!!
baherus [9]

Answer:

Mass is the correct answer.

Explanation:

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4 0
3 years ago
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Balancing equations<br>​
kolbaska11 [484]

Answer:

Tips for Balancing Chemistry Equations You may only put numbers in front of the molecules. You can never alter the subscript, as it would alter the formula. ... Begin by counting and making note of the elements present on each side of the equation. Count the number of molecules of each element on both sides of the equation. More items...

Explanation:

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3 years ago
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