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3 years ago

15

Here's a quick story if a boy walks to the woods at night and slender man comes along what is most likely to happen put your ans

wers in the comments.

2 answers:

ANEK [815]3 years ago

8 0

Answer:

the boy would go missing

Vsevolod [243]3 years ago

8 0

Answer: Slender man converts the boy to christianity

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When a speeding truck hits a stationary car, the car is deformed and heat is generated. What can you say about the kinetic energ

cluponka [151]

nothing

Explanation:

we can say that it was certainly bad for the shopkeeper obviously and we should not be making questions about the physics behind that accident and should call the cops or 911

3 0

3 years ago

"KATZPSEF1 7.P.053.MI. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Two black holes (the remains of exploded stars), separated by

eduard

Answer:

There are two possible solutions.

M1 = 4.68*10^30kg, M2 = 5.53*10^30kg

M1 = 5.53*10^30kg, M2 = 4.7*10^29kg

Explanation:

In order to find the mass of each black hole, you take into account the gravitational force between them and the sum of their masses.

You use the formula for the gravitational force between two masses:

$F_g=G\frac{M_1M_2}{r^2}$ (1)

G: Cavendish's constant = 6.674*10^-11 m^3/kg.s^2

M1, M2: mass of each black hole = ?

r: distance between the black holes = 10.0 AU = 10.0(1.50*10^11m) = 1.5*10^12m

Fg: gravitational force between the black holes = 7.70*10^25N

Furthermore, you take into account that the sum of the masses M1 and M2 is:

M1 + M2 = 6.00*10^30 kg (2)

You solve the equation (2) for M2.

$M_2=6.00*10^{30}-M_1$

Next, you replace the obtained expression for M2 into the equation (1) and solve for M1, as follow (for simplicity, you do not add the units):

$F_g=G\frac{M_1(6.00*10^{30}-M_1)}{r^2}\\\\\frac{r^2F_g}{G}=6.00*10^{30}M_1-M_1^2\\\\\frac{(1.5*10^{12})^2(7.70*10^{25})}{(6.674*10^{-11}}=6.00*10^{30}M_1-M_1^2\\\\2.59*10^{60}=6.00*10^{30}M_1-M_1^2\\\\M_1^2-6.00*10^{30}M_1+2.59*10^{60}=0$

Then, you have obtained a quadratic polynomial. You solve it with the quadratic formula:

$M_1=\frac{-(-6.00*10^{30})\pm \sqrt{(-6.00*10^{30})^2-4(1)(2.59*10^{60}))}}{2(1)}\\\\M_1=\frac{6.00*10^{30}\pm 5.06*10^{30}}{2}\\\\M_1=4.68*10^{29}\\\\M_1=5.53*10^{30}$

Both results are consistent, then the mass of one black hole can be 4.68*10^30kg and also 5.53*10^30kg.

The other black hole has a mass of:

$M_2=6.00*10^{30}kg-4.68*10^{29}kg=5.53*10^{30}kg\\\\M_2=6.00*10^{30}kg-5.53*10^{30}kg=4.7*10^{29}kg$

Hence, you have a pair of solutions:

M1 = 4.68*10^30kg, M2 = 5.53*10^30kg

M1 = 5.53*10^30kg, M2 = 4.7*10^29kg

3 0

3 years ago

Describe the difference between ‘conventional current’ and ‘electron flow’

Tamiku [17]

Answer:

Screenshot attached

Explanation:

6 0

3 years ago

If the planes of a crystal are 3.50 (1 A= 10^-10m = Ångstrom unit) apart, what wavelength of electromagnetic waves are needed so

goldenfox [79]

Answer:

λ = 2.62 x 10⁻¹⁰ m = 0.262 nm

Explanation:

We can use Bragg's Law's equation to solve this problem. The Bragg's Law's equation is written as follows:

mλ = 2d Sin θ

where,

m = order of reflection = 1

λ = wavelength = ?

d = distance between the planes of crystal = 3.5 x 10⁻¹⁰ m

θ = strike angle of waves on plane = 22°

Therefore, substituting the respective values in the equation, we get:

(1)λ = (2)(3.5 x 10⁻¹⁰ m)(Sin 22°)

<u>λ = 2.62 x 10⁻¹⁰ m = 0.262 nm</u>

4 0

3 years ago

What region of the electromagnetic spectrum contains wavelengths the size of an atom? (10^-10 meters) What frequency does this w

DENIUS [597]

If a photon has a wavelength of about 10^-10 meters, it would be certainly in the X rays region and it would have a frequency of 2.99792458x10^18 Hz, that you can easily calculate using the relation that states that the product of the wavelength and the frequency of an electromagnetic wave aka light is always equal to 299,792,458 m/s which is the exact value of the speed of light!

3 0

4 years ago