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Harman [31]
3 years ago
12

A compound that contains only carbon, hydrogen and oxygen has the following

Chemistry
2 answers:
Mariulka [41]3 years ago
8 0

C6H8O6 i think so might be (C)

Aneli [31]3 years ago
8 0

Answer:  A)  C5H8O2

Explanation:  Let's assume we have 100 grams of the unknown compound.  We can then find grams for each element by multiply it's percentage times 100g.  (e.g., carbon at 60% gives 60 grams of C).  Then divide the mass of each element by it's molar mass.  That will normalize the number of that element in relation to the others.  E,g,, the 60 grams of carbon, divided by its molar mass of 12.01 g/mole gives 5 moles of C atoms.  For H we get 8, and for O we get 2.  That gives us the empirical formula C5H8O2

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A tank is filled with gasoline to a depth of exactly 2 feet. The tank is a cylinder resting horizontally on its side, with its c
inna [77]

Answer:

The volume of the gasoline in the tank is 18.85 cubic feet

Explanation:

The tank is a cylinder. The equation for calculating the cylinder volumen is πr²*h, r is radius and h is height. π is approximately 3.1416. So,  The tank is  resting horizontally on its side, its radius is 2 feet/2= 1 feet. h=a tank long= 6 feet.

With equation:

Vol gasoline=3.1416*1²*6=18.85 feet ³

I hope my answer helps you

6 0
3 years ago
A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temp
vichka [17]

Answer:

The balanced chemical equation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat of combustion per gram of phenol is 32.454 kJ/g

Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = T_1= 21.36^oC

Final temperature of the calorimeter = T_2= 26.37^oC

Heat absorbed by calorimeter = Q

Q=C\times \Delta T

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol

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3 years ago
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Answer:

Explanation:

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