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2 years ago

A compound that contains only carbon, hydrogen and oxygen has the following

Chemistry

2 answers:

Mariulka [41]2 years ago

8 0

C6H8O6 i think so might be (C)

Aneli [31]2 years ago

8 0

Answer: A) C5H8O2

Explanation: Let's assume we have 100 grams of the unknown compound. We can then find grams for each element by multiply it's percentage times 100g. (e.g., carbon at 60% gives 60 grams of C). Then divide the mass of each element by it's molar mass. That will normalize the number of that element in relation to the others. E,g,, the 60 grams of carbon, divided by its molar mass of 12.01 g/mole gives 5 moles of C atoms. For H we get 8, and for O we get 2. That gives us the empirical formula C5H8O2

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What is the maximum number of grams of copper that could be produced by the reaction of 30.0 of copper oxide with excess methane

Solnce55 [7]

Answer: 24.13 g Cu

Explanation:

<u>Given for this question:</u>

M of CuO = 30 g

m of CuO = 79.5 g/mol

Number of moles of CuO = (given mass ÷ molar mass) = (30 ÷ 79.5) mol

= 0.38 mol

The max number of CuO (s) that can be produced by the reaction of excess methane can be solved with this reaction:

CuO(s) + CH4(l) ------> H2O(l) + Cu(s) + CO2(g)

The balanced equation can be obtained by placing coefficients as needed and making sure the number of atoms of each element on the reactant side is equal to the number of atoms of each element on the product side

4CuO(s) + CH4(l) ----> 2H2O(l) + 4Cu(s) + CO2(g)

From the stoichiometry of the balanced equation:

4 moles of CuO gives 4 moles of Cu

1 mole of CuO gives 1 mol of Cu

0.38 mol of CuO gives 0.38 mol of Cu

Therefore, the grams of Cu that can be produced = 0.38 × molar mass of Cu

= 0.38 × 63.5 g

= 24.13 grams

Therefore, 24.13 grams of copper could be produced by the reaction of 30.0 of copper oxide with excess methane

4 0

1 year ago

Describe the pattern of temperature changes within the layers of the atmosphere. Why do you think temperature changes follow thi

ser-zykov [4K]

Answer:

The atmosphere refers to the gaseous envelope of earth, comprised of variable gases with definite proportions. The layers of the earth's atmosphere are as follows-

Troposphere- This layer starts from the ground and extends up to a height of about 10 km. Here, the temperature decreases with the increasing altitude. All the weather phenomenon takes place in this layer.

Stratosphere- It starts from 10 km and extends up to a height of about 50 km. Here the temperature increases as the altitude increase. This is because of the presence of the ozone layer that receives the harmful UV radiation emitted from the sun.

Mesosphere- This layer extends from a height of about 50 km to about 80 km above the earth's surface. Here, again the temperature decreases with the increasing altitude.

Thermosphere- This layer starts from a height of about 80 km and extends up to about 500 km above the ground surface. In this region again the temperature increases with the increasing elevation.

Exosphere- This layer ranges from about 500 km to 10,000 km above the earth's surface. Here, the temperature gradually increases with the increasing height.

This variation in temperature occurs because of the certain reason. In the troposphere and the mesosphere, the temperature decreases with height because the pressure and height are inversely proportional to each other. The stratosphere experiences increasing temperature because of the presence of the ozone layer that is responsible for holding the greenhouse gases and the harmful UV radiation. The thermosphere and the exosphere experience high temperatures because of the receiving of the direct sunlight. Due to these above reason, there occurs this temperature change in a unique pattern.

6 0

3 years ago

What is the mass of a 1.68-l sample of a liquid that has a density of 0.921g/ml?

Gwar [14]

Hey there!

Volume in mL :

1.68 L * 1000 => 1680 mL

Density = 0.921 g/mL

Therefore:

Mass = density * Volume

Mass = 0.921 * 1680

Mass = 1547.28 g

7 0

3 years ago

Write the name of the alkyne next to the drawing of the molecule. (2 points)

azamat

1) 1-Pentyne

2) But-2-yne

3) Ethyne

4) 1-Propyne

5) 1-Butyne

6) Pent-2-yne

<h3>What is alkyne?</h3>

Molecules that contain a triple bond between two carbon atoms are known as alkynes.

1) The number of carbon on the longest chain = 5, (two carbon atoms between the triple bond) therefore the prefix is pen-

The functional group is the triple bond on the first carbon with the suffix -yne

The name of the compound is 1-Pentyne

2) There are 4 carbon atoms on the longest chain, therefore, the prefix is but-

The location of the triple bond functional group (suffix; -yne) is on the second carbon atom

Therefore, the name of the compound is But-2-yne

3) The triple bond functional group is between the only two carbon atoms, therefore, the name is Ethyne

4) The number of carbon atoms = 3, with a prefix prop-, and the functional group on the first carbon atom on the longest chain is the triple bond, with suffix -yne

Therefore, the name of the compound is 1-Propyne

5) The number of carbon atoms on the longest chain = 4, the prefix is but-

The location of the triple bond functional group (suffix -yne) is on the first carbon atom

Therefore, the name is 1-Butyne

6) The number of carbon atoms on the longest chain = 5, the prefix of the compound is pen-

The location of the triple bond functional group (suffix; -yne) is on the second carbon atom, therefore;

The name of the compound is Pent-2-yne

Learn more about alkyne here:

brainly.com/question/23508203

#SPJ1

6 0

2 years ago

As with other ionic compounds, potassium bromate, KBrO3, dissociates into ions when it dissolves in water. If 13.8 g of KBrO3 is

chubhunter [2.5K]

Answer:

ΔH of dissociation is 38,0 kJ/mol

Explanation:

The dissociation reaction of KBrO₃ is:

<em>KBrO₃ → K⁺ + BrO₃⁻ </em>

This dissolution consume heat that is evidenced with the decrease in water temperature.

The heat consumed is:

q = CΔTm

Where C is specific heat of water (4,186 J/mol°C)

ΔT is the temperature changing (18,0°C - 13,0°C = 5,0°C)

And m is mass of water (150,0 mL ≈ 150,0 g)

Replacing, heat consumed is:

q = 3139,5 J ≡ 3,14 kJ

13,8 g of KBrO₃ are:

13,8 g×(1mol/167g) = 0,0826 moles

Thus, ΔH of dissociation is:

3,14kJ / 0,0826mol = <em>38,0 kJ/mol</em>

I hope it helps!

3 0

3 years ago