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3 years ago

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Two forces act on a 8.50-kg object. One of the forces is 14.0 N. If the object accelerates at 3.50 m/s2 , what is the greatest p

ossible magnitude of the other force

1 answer:

astra-53 [7]3 years ago

7 0

Answer:

The magnitude of the other force is 43.75 N.

Explanation:

Given that,

Mass of the object, m = 8.5 kg

Force 1, $F_1=14\ N$

Acceleration of the object, $a=3.5\ m/s^2$

To find,

The greatest possible magnitude of the other force.

Solution,

Let $F_2$ is the magnitude of other force that is acting on the object. For the greatest force, the two forces must be act in opposite direction such that :

$F_2-F_1=ma$

$F_2=ma+F_1$

$F_2=14+8.5\times 3.5$

$F_2=43.75\ N$

So, the magnitude of the other force is 43.75 N.

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Read 2 more answers

A 0.300 kg block is pressed against a spring with a spring constant of 8050 N/m until the spring is compressed by 6.00 cm. When

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$\frac{1}{2}\cdot k \cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}$

$v = x\cdot \sqrt{\frac{k}{m} }$

$v = (0.06\,m)\cdot \sqrt{\frac{8050\,\frac{N}{m} }{0.3\,kg} }$

$v \approx 9.829\,\frac{m}{s}$

The radius of the circular loop is:

$\Sigma F_{r} = -90\,N -(0.3\,kg)\cdot (9.807\,\frac{m}{s^{2}} ) = -(0.3\,kg)\cdot \frac{v^{2}}{R}$

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