We have that all except Uranium is Stable
From the question we are told
Classify the following nuclei into stable or unstable.
- Generally a nuclei is made up of Neutrons and Protons
- A stable nuclei is one with its Protons and Neutrons equal or Very close
Generally the equation for Stable Nuclei is mathematically given as
n=p
Therefore
For U
P=92
N=238-92
N=146
Therefore Unstable
For N
P=7
N=9
Therefore Stable
For Be
P=4
N=6
Therefore Stable
For Ne
P=10
N=10
Therefore Stable
For Al
P=13
N=14
Therefore Stable
For Ar
P=18
N=21
Therefore Stable
For Ni
P=28
N=36
Therefore Stable
For O
P=8
N=7
Therefore Stable
For He
P=2
N=2
Therefore Stable
For Sc
P=21
N=20
Therefore Stable
For Li
P=3
N=3
Therefore Stable
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Answer:
Explanation:
Wave Period and Frequency In this video Paul Andersen explains how the period is the time between wave and the frequency is the number of ... Your browser does not currently recognize any of the video formats available. ... Show less Show more ... Waves: Light, Sound, and the nature of Reality.
The kinetic energy for a large vehicle is different from that of a smaller vehicle, assuming that the vehicles are travelling at the same speed and stopping the same distance. This is because for a larger vehicle the kinetic energy is higher, as the mass for a larger vehicle, is more than the smaller vehicle.
Answer:
The gauge pressure is 1511.11 psi.
Explanation:
Given that,
Flow rate = 94 ft³/min
Diameter d₁=3.3 inch
Diameter d₂ = 5.2 inch
Pressure P₁= 15 psi
We need to calculate the pressure on other side
Using Bernoulli equation
![P_{1}+\dfrac{1}{2}\rho v_{1}^2=P_{2}+\dfrac{1}{2}\rho v_{2}^2](https://tex.z-dn.net/?f=P_%7B1%7D%2B%5Cdfrac%7B1%7D%7B2%7D%5Crho%20v_%7B1%7D%5E2%3DP_%7B2%7D%2B%5Cdfrac%7B1%7D%7B2%7D%5Crho%20v_%7B2%7D%5E2)
We know that,
![V=Av](https://tex.z-dn.net/?f=V%3DAv)
![v=\dfrac{V}{A}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7BV%7D%7BA%7D)
Where, V = volume
v = velocity
A = area
Put the value of v into the formula
![P_{1}+\dfrac{1}{2}\rho (\dfrac{V}{A_{1}})^2=P_{2}+\dfrac{1}{2}\rho (\dfrac{V}{A_{2}})^2](https://tex.z-dn.net/?f=P_%7B1%7D%2B%5Cdfrac%7B1%7D%7B2%7D%5Crho%20%28%5Cdfrac%7BV%7D%7BA_%7B1%7D%7D%29%5E2%3DP_%7B2%7D%2B%5Cdfrac%7B1%7D%7B2%7D%5Crho%20%28%5Cdfrac%7BV%7D%7BA_%7B2%7D%7D%29%5E2)
Put the value into the formula
![15+\dfrac{1}{2}\times0.36\times(\dfrac{2707.2\times4}{\pi\times(3.3)^2})^2=P_{2}+\dfrac{1}{2}\times0.36\times(\dfrac{2707.2\times4}{\pi\times(5.2)^2})^2](https://tex.z-dn.net/?f=15%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes0.36%5Ctimes%28%5Cdfrac%7B2707.2%5Ctimes4%7D%7B%5Cpi%5Ctimes%283.3%29%5E2%7D%29%5E2%3DP_%7B2%7D%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes0.36%5Ctimes%28%5Cdfrac%7B2707.2%5Ctimes4%7D%7B%5Cpi%5Ctimes%285.2%29%5E2%7D%29%5E2)
![P_{2}=15+\dfrac{1}{2}\times0.036\times(\dfrac{2707.2\times4}{\pi\times(3.3)^2})^2-\dfrac{1}{2}\times0.036\times(\dfrac{2707.2\times4}{\pi\times(5.2)^2})^2](https://tex.z-dn.net/?f=P_%7B2%7D%3D15%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes0.036%5Ctimes%28%5Cdfrac%7B2707.2%5Ctimes4%7D%7B%5Cpi%5Ctimes%283.3%29%5E2%7D%29%5E2-%5Cdfrac%7B1%7D%7B2%7D%5Ctimes0.036%5Ctimes%28%5Cdfrac%7B2707.2%5Ctimes4%7D%7B%5Cpi%5Ctimes%285.2%29%5E2%7D%29%5E2)
![P_{2}=1525.8\ psi](https://tex.z-dn.net/?f=P_%7B2%7D%3D1525.8%5C%20psi)
We need to calculate the gauge pressure
Using formula of gauge pressure
![P_{g}=P_{ab}-P_{atm}](https://tex.z-dn.net/?f=P_%7Bg%7D%3DP_%7Bab%7D-P_%7Batm%7D)
Put the value into the formula
![P_{g}=1525.8-14.69](https://tex.z-dn.net/?f=P_%7Bg%7D%3D1525.8-14.69)
![P_{g}=1511.11\ psi](https://tex.z-dn.net/?f=P_%7Bg%7D%3D1511.11%5C%20psi)
Hence, The gauge pressure is 1511.11 psi.