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Gala2k [10]
3 years ago
12

Is the energy of a wave is calculated by squaring the frequency of the wave?

Physics
1 answer:
Misha Larkins [42]3 years ago
5 0
Nope.
Energy is directly proportional to frequency. and when you calculate energy, you multiply frequency with a constant number called "Planck's Constant"

E = hf

Hope this helps!
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NEED HELP
ch4aika [34]

Answer: C.

Explanation:

Just took quiz

8 0
3 years ago
The conducting path between the right hand and the left hand can be modeled as a 9.0-cm-diameter, 140-cm-long cylinder. The aver
Crank

Answer:

The potential difference is 121.069 V

Solution:

As per the question:

Diameter of the cylinder, d = 9.0 cm = 0.09 m

Length of the cylinder, l = 40 cm = 1.4 m

Average Resistivity, \rho = 5.5\ \Omega-m

Current, I = 100 mA = 0.1 A

Now,

To calculate the potential difference between the hands:

Cross- sectional Area of the Cylinder, A = \pi (\frac{d}{2})^{2} = 6.36\times 10^{- 3}\ m^{2}

Resistivity is given by:

\rho = R\frac{A}{l}

R = \rho \frac{l}{A}

R = 5.5\times \frac{1.4}{6.36\times 10^{- 3}} = 1210.69\ \Omega

Now, using Ohm's Law:

V = IR

V = 0.1\times 1210.69 = 121.069\ V

4 0
3 years ago
Which of the following is most closely related to the specific heat of a substance?A. its temperatureB. its melting pointC. its
swat32

Answer:

option (C)

Explanation:

The amount of heat required to raise the temperature of substance of unit mass by unit degree is called specific heat of that substance.

Its SI unit is Joule / Kg °C.

Every material has a constant value of specific heat.

So, option (c) is correct.

4 0
3 years ago
What is a horizontal segment meaning on a position vs. time graph?
sergeinik [125]

The velocity of the object is zero (the object is at rest)

Explanation:

A position vs time graph represents the motion of an object; in particular:

  • The position of the object x(t) is represented on the y-axis
  • The time t is represented on the x-axis

For a position-time graph, the slope of the graph is given by

m=\frac{\Delta x}{\Delta t}

where

\Delta x is the change in position

\Delta t is the change in time

However, we see that this is equivalent to the definition of velocity:

v=\frac{\Delta x}{\Delta t}

Therefore, the slope of  a position-time graph is equivalent to the velocity of the object.

And so, a horizontal segment on a position vs time graph means that the object has zero velocity (because the slope is zero).

Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

4 0
3 years ago
wo parallel-plate capacitors C1 and C2 are connected in parallel to a 12.0 V battery. Both capacitors have the same plate area o
tresset_1 [31]

Complete Question

Two parallel-plate capacitors C1 and C2 are connected in parallel to a 12.0 V battery. Both capacitors have the same plate area of 5.30 cm2 and plate separation of 2.65 mm. However, the first capacitor C1 is filled with air, while the second capacitor C2 is filled with a dielectric that has a dielectric constant of 2.10.

(a) What is the charge stored on each capacitor

 (b)  What is the total charge stored in the parallel combination?

Answer:

a

   i    Q_1 =  2.124 *10^{-11} \  C

   ii    Q_2 =  4.4604 *10^{-11} \ C

b

  Q_{eq} = 6.5844 *10^{-11} \ C

Explanation:

From the question we are told that

   The  voltage of the battery is  V  = 12.0  \ V

    The  plate area of each capacitor is  A  =  5.30 \ cm^2  =  5.30 *10^{-4} \ m^2

    The  separation between the plates is  d =  2.65 \ mm =  2.65 *10^{-3} \ m

     The permittivity of free space  has a value  \epsilon_o  =  8.85 *10^{-12} \  F/m

     The  dielectric constant of the other material is  z =  2.10

The  capacitance of the  first capacitor is mathematically represented as

       C_1  =  \frac{\epsilon  *  A }{d }

substituting values

        C_1  =  \frac{8.85 *10^{-12 } *   5.30 *10^{-4} }{2.65 *10^{-3} }

       C_1  =  1.77 *10^{-12} \  F

The  charge stored in the first capacitor is  

       Q_1 =  C_1 *  V

substituting values

        Q_1 =  1.77 *10^{-12} * 12

       Q_1 =  2.124 *10^{-11} \  C

The capacitance of the second  capacitor is mathematically represented as

       C_2  =  \frac{ z * \epsilon  *  A }{d }

substituting values

       C_1  =  \frac{  2.10 *8.85 *10^{-12 } *   5.30 *10^{-4} }{2.65 *10^{-3} }

       C_1  =  3.717 *10^{-12}  \ F

The  charge stored in the second capacitor is  

      Q_2 =  C_2 *  V

substituting values

     Q_2 = 3.717*10^{-12} *  12

     Q_2 =  4.4604 *10^{-11} \ C

Now  the total charge stored in the parallel combination is mathematically represented as

     Q_{eq} =  Q_1 + Q_2

substituting values

    Q_{eq} =  4.4604 *10^{-11} + 2.124*10^{-11}

     Q_{eq} = 6.5844 *10^{-11} \ C

7 0
3 years ago
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