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2 years ago

Is the energy of a wave is calculated by squaring the frequency of the wave?

1 answer:

5 0

Nope.
Energy is directly proportional to frequency. and when you calculate energy, you multiply frequency with a constant number called "Planck's Constant"

E = hf

Hope this helps!

You might be interested in

What was the measurement of the wavelength and amplitude respectively?

SpyIntel [72]

<h3>Answer</h3>

option C)

The wavelength has a length between 7.0 cm and 8.0 cm and the amplitude lies between 1.0 cm and 2.0 cm.

<h3>Explanation</h3><h2>1)</h2>

The amplitude of a wave is the height of a wave as measured from the highest point on the wave, peak, to the rest point or from the lowest point on the wave, trough, to the rest point.

By looking at the image

rest point is at 5cm and crest is at 3.3 cm (y-axis)

so amplitude = 5 - 3.3

= 1.7 cm (approximately)

Wavelength refers to the length of a wave from one peak to the next.

one crest is at 2cm and the other crest is at 10cm (x-axis)

so wavelength = 10 - 2

= 8 cm (approximately)

<h3 />

5 0

2 years ago

Two balls having diﬀerent masses reach the same height when shot into the air from

Alinara [238K]

A.

Kinematics is independent of mass, in most cases.

6 0

2 years ago

The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 2.0 rev/s in 10.0 s. At th

Arte-miy333 [17]

Answer:

22 revolutions

Explanation:

2 rev/s = 2*(2π rad/rev) = 12.57 rad/s

The angular acceleration when it starting

$\alpha_a = \frac{\Delta \omega}{\Delta t} = \frac{12.57}{10} = 1.257 rad/s^2$

The angular acceleration when it stopping:

$\alpha_o = \frac{\Delta \omega}{\Delta t} = \frac{-12.57}{12} = -1.05 rad/s^2$

The angular distance it covers when starting from rest:

$\omega^2 - 0^2 = 2\alpha_a\theta_a$

$\theta_a = \frac{\omega^2}{2\alpha_a} = \frac{12.57^2}{2*1.257} = 62.8 rad$

The angular distance it covers when coming to complete stop:

$0 - \omega^2 = 2\alpha_o\theta_o$

$\theta_o = \frac{-\omega^2}{2\alpha_o} = \frac{-12.57^2}{2*(-1.05)} = 75.4 rad$

So the total angular distance it covers within 22 s is 62.8 + 75.4 = 138.23 rad or 138.23 / (2π) = 22 revolutions

6 0

3 years ago

You are watching a television show about Navy pilots. The narrator says that when a Navy jet takes off, it accelerates because t

zepelin [54]

You are watching a television show about Navy pilots. The narrator says that when a Navy jet takes off, the average force on the jet is due to the catapult is mathematically given as

What is the average force on the jet is due to the catapult?

Generally, the equation for acceleration is mathematically given as

$a=\frac{vf^2-vi^2}{2s}\\\\\Therefore\\\\a=\frac{69.29^2-0^2}{2(90}\\\\a=26.673m/s^2$

In conclusion, The force

F=m*a

F=15100*26.673

F=40272.3N

F 402 KN