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torisob [31]
3 years ago
7

What is the WWF doing to help protect turtle eggs? (Site 1)

Physics
1 answer:
ivolga24 [154]3 years ago
4 0
<h3><u>WWF in protection of Turtle eggs:</u></h3>

World Wildlife Fund (WWF) is an NGO that primly aims wildlife preservation. To protect marine turtles and avoid its poaching, WWF works through TRAFFIC, the Wildlife trade monitoring network.  

Turtle eggs are highly demanded for human consumption, either raw or as expensive dishes in star rated restaurants. WWF along with TRAFFIC promotes ecotourism by raising awareness to stop preferring turtle products. It establishes and strengthens MPA's (Marine Protected areas) areas where turtle nesting is primarily observed and thus turtles are free and safe to nest, feed and migrate.

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An alternator provides 20 A of peak current at 100 V peak AC to a resistive electric heater. How much heating power is delivered
Liono4ka [1.6K]

-- The resistance of the heater is (volts/current) = 5 ohms

-- The heating (RMS) value of a sinusoidal AC is V(peak)/√2 .  For this particular alternator, V(peak)=100V, so the heating (RMS) equivalent is 70.71 V.

-- The heating power delivered to the electric heater is (E²/R).

Power = (100/√2)² / 5

Power = 5,000 / 5

<u>Power = 1,000 watts </u>

6 0
3 years ago
Which conclusion is supported by the data in the table?
vaieri [72.5K]

Answer:

B. More African Americans became registered to vote in Southern states.

Explanation:

8 0
3 years ago
Could you help me with this question?
Scorpion4ik [409]

Answer:

Magnitude of static friction force is 70 sin40° = 44.99 N.  

No, it is not necessary that it is maximum static friction.

Normal force is equal to 70 cos40° = 53.62 N.

Explanation:

We apply newton law of moton equation along the plane and perpendicular to plane;

Along the plane,

70 sin 40° = f_{r}  ---------------(1)

70 cos 40° = N --------------(2)

f_{r}_{max} = μN -----------------(3)

So, it depends on the value of μ that the friction is maximum or not .

7 0
2 years ago
What is the smallest radius of an unbanked (flat) track around which a bicyclist can travel if her speed is 29.5 km/h and the μs
Yakvenalex [24]

Answer:

Radius=15.773 m

Explanation:

Given data

v=29.5 km/h=8.2 m/s

μs=0.435

To find

Radius R

Solution

The acceleration is a centripetal acceleration  which is experienced by the bicycle given by

a=v^{2}/R

This acceleration is only due to static force which given as

f=ma\\f=m(v^{2}/R )

The maximum value of the static force is given as

Fs_{max}=u_{s}F_{N}

where

FN is normal force equal to mass*gravity

Therefore when the car is on the verge of sliding

f=fs_{max}\\ m(v^{2}/R )=u_{s}mg

Therefore the minimum radius should be found by the bicycle move without  sliding

So

v^{2}/R=u_{s}g\\  R=v^{2}/u_{s}g\\R=(8.2)^{2}/(0.435*9.8)\\R=15.773m

8 0
3 years ago
A uniform solid sphere has a moment of inertia I about an axis tangent to its surface. What is the moment of inertia of this sph
arsen [322]

Answer:

option E

Explanation:

given,

I is moment of inertia about an axis tangent to its surface.

moment of inertia about the center of mass

I_{CM} = \dfrac{2}{5}mR^2.....(1)

now, moment of inertia about tangent

I= \dfrac{2}{5}mR^2 + mR^2

I= \dfrac{7}{5}mR^2...........(2)

dividing equation (1)/(2)

\dfrac{I_{CM}}{I}= \dfrac{\dfrac{2}{5}mR^2}{\dfrac{7}{5}mR^2}

\dfrac{I_{CM}}{I}=\dfrac{2}{7}

I_{CM}=\dfrac{2}{7}I

the correct answer is option E

4 0
3 years ago
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