Answer:
77.08 C
Explanation:
= mass of the water = 500 g = 0.5 kg
= specific heat of water = 4186 J/(kg °C)
= Rate of change of temperature = 3 °C /min = (3/60 ) °C /s = 0.05 °C /s
= thermal conductivity of glass = 0.84
= Area of the element = 0.090 m²
= thickness of the element = 1.5 mm = 0.0015 m
= Temperature inside = 75 °C
= Temperature outside = ?
Using conservation of energy
Heat gained by water = Heat transferred through glass
Answer:
47.48 J/g/K or 4.74 × 10⁴J/Kg/K
Explanation:
C(specific heat capacity)= Q(quantity of heat)/M(mass) × ∆T(change in temperature, Kelvin)
Q= 8000J
M= 46g or 46 ×10^-3Kg
T1= 24°C = 297K
T2 = 28°C = 301K
∆T = 301-297
= 4K
C= 8000/46 × 4
= 47.48 J/g/K or 4.74 × 10⁴J/Kg/K
The answer is the letter "C" ( I have honors science I am good at this type of stuff )
Hope I helped :) ( ask me for help when u need it :)