Answer:
d) the second law of thermodynamics
Explanation:
Here we take an example
The entropy represents a measurement of the energy dispersal in the system. Also, the campfire would an entropy example. The burning of the solid wood and then it became the ash, smoke and gases this all would be spread the energy to the outward as compared to the solid fuel
Therefore as per the given statement, the correct option is d.
Answer:
the rate of heat transfer after the system achieves steady state is -3.36 kW
Explanation:
Given the data in the question;
mass of water m = 50 kg
N = 300 rpm
Torque T = 0.1 kNm
V = 110 V
I = 2 A
Electric work supplied W₁ = PV = 2 × 110 = 220 W = 0.22 kW
Now, work supplied by paddle wheel W₂ is;
W₂ = 2πNT/60
W₂ = (2π × 0.1 × 300) / 60
W₂ = 188.495559 / 60
W₂ = 3.14 kW
So the total work will be;
W = 0.22 + 3.14
W = 3.36 kW
Hence total work done on the system is 3.36 kW.
At steady state, the properties of the system does not change so the heat transfer will be 3.36 KW.
The heat will be rejected by the system so the sign of heat will be negative.
i.e Q = -3.36 kW
Therefore, the rate of heat transfer after the system achieves steady state is -3.36 kW
Answer:
The force F1 = 10 N when d1 = 4 m. The square of 4 m is d1² = 16 m². When d = 2 m, its square is d2² = 4 m². Solving for F2
F2× d2² = F1× d1²
F2 × 4m² = 10 N × 16 m²
F2 = (10 N × 16 m^2) / 4 m² F2
= 10 N× (16 m² /4 m²)
F2 = 10 N × 4
F2 = 40 N
The gravitational force produced when they are kept 2 meters apart is 40 N.
The formula we will be using is:
Final Velocity = Initial Velocity + Acceleration * Time
v = u + at
u = v - at = 9.81 - 6.24*0.3 = 7.938 m/s
Answer:
2 Kilometers
Explanation:
The mass of the torpedo isn't really required here in this scenario.
Basically, the formula, Distance = Speed x Time is used here
So, Distance = 20 m/s x 100 s
We get 2000 metres
Convert that into kilometers if required and you get 2 kilometers.
Hope this helped.